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frutty [35]
3 years ago
6

Someone please please help help me please please help help please please help me please please ASAP ASAP!!!!

Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

okay so what you want to do is lie by saying you did it.

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Whαt ís thє vαluє σf х ?<br><br><img src="https://tex.z-dn.net/?f=x%20%7B%7D%5E%7B2%7D%20%20%20-%20%20%5C%3A%2025%20%3D%20144" i
Zigmanuir [339]

Answer:

hey mate!!

Step-by-step explanation:

x

2

−25=144

X^2=144+25

x^2=169

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x=13

Sorry mate check out the answer !

7 0
3 years ago
Read 2 more answers
Keisha and Angelica bought a basket of apples. Keisha bought 5
MA_775_DIABLO [31]

Answer:

1. C 2.B .  

Step-by-step explanation:

answer : 1. A+ 5/4 +19/4 ,,,,, 2. 14/4 = 7/2

Hope it helps :)

ANSWER: 2

Answer:

What is the equation that models this scenario?

✔ A + 5/4 = 19/4

and

How many pounds of apples did Angelica buy?

✔ 14/4 = 7/2

Step-by-step explanation:

Hope this helps!! :)

4 0
1 year ago
Read 2 more answers
Is the answer English?
Vesnalui [34]
Yes indeed it is. Your correct
3 0
3 years ago
21) Jim and his uncle went to the circus. Together they spent
SCORPION-xisa [38]
3/30 or 1/10 or $3
There all the same answer just different ways
The first one is unsimplified The second one is simplified The last one is in money form
3 0
3 years ago
Construct the discrete probability distribution for the random variable described. Express the probabilities as simplified fract
lisov135 [29]

Answer:

P(X = 0) = 0.03125

P(X = 1) = 0.15625

P(X = 2) = 0.3125

P(X = 3) = 0.3125

P(X = 4) = 0.15625

P(X = 5) = 0.03125

Step-by-step explanation:

For each toss, there are only two possible outcomes. Either it is tails, or it is not. The probability of a toss resulting in tails is independent of any other toss, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Fair coin:

Equally as likely to be heads or tails, so p = 0.5

5 tosses:

This means that n = 5

Probability distribution:

Probability of each outcome, so:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.5)^{0}.(0.5)^{5} = 0.03125

P(X = 1) = C_{5,1}.(0.5)^{1}.(0.5)^{4} = 0.15625

P(X = 2) = C_{5,2}.(0.5)^{2}.(0.5)^{3} = 0.3125

P(X = 3) = C_{5,3}.(0.5)^{3}.(0.5)^{2} = 0.3125

P(X = 4) = C_{5,4}.(0.5)^{4}.(0.5)^{1} = 0.15625

P(X = 5) = C_{5,5}.(0.5)^{5}.(0.5)^{0} = 0.03125

5 0
2 years ago
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