Their are 6 equilateral triangles in a regular hexagon:
The area of one triangle = (x²√3)/4, then:
1st answer: The area of the hexagon base: is 6 TIMES the area of one equilateral triangle [or, needed for 2nd, question, TOT AREA:(6x²√3)/4] = (3x²√3)/2] unit²
2nd answer: :
Volume of pyramid: (base area)(height)/3
Volume of pyramid: (3x²√3).(3x)/3 (because height = 3x, given)
Then Volume of pyramid= 3x³√3 unit³.
3 is the answer for the second question
and 6 for the 1st
6x + 4y = 12...subtract 6x from both sides
4y = -6x + 12 ...divide both sides by 4
(4/4)y = (-6/4)x + 12/4...reduce
y = -3/2x + 4 <== y = mx + b
Answer:
1yes
2no
3yes
Step-by-step explanation:
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The answer is D
Explanation:5x^5-44x^3-9x=0
X(5x^2+1)(x-3)(x+3)=0
X(x+3)(x-3)=0
X=0,x=-3,x=3