Answer:
86
Step-by-step explanation:
180 - 94 = 86
Answer:

Step-by-step explanation:
h + 4 ≤ 20
Subtract 4 from both sides.
h ≤ 20 − 4
Subtract 4 from 20 to get 16.

Hope it helps and have a great day! =D
~sunshine~
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
x = 18 + 9y/2
x-18 = 9y/2
(x-18)x2=9y
2(x-18)=9y
2(x-18) / 9 = y
y= 2(x-18)/9
Step-by-step explanation:
<em>Simplify 9/2y to 9y/2</em>
<em>Then Subtract 18 from both sides</em>
<em>Now Multiply both sides by 2</em>
<em>Then Regroup the terms</em>
<em>now divide both sides by 9</em>
<em>Then you will Switch sides</em>
Answer:



Step-by-step explanation:
First, let's look at the largest triangle (two smaller triangles are combined) to solve for
. Since the sum of the angles in a triangle adds up to
, we can write the equation:



Looking at the smaller triangle on the left,
(exterior angle) is the sum of the two opposite interior angles of the triangle on the left:


Since
is the exterior angle of the triangle on the right, it is equivalent to the sum of the opposite interior angles of that triangle:



Hope this helps :)