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Gnesinka [82]
3 years ago
9

Determine the number of solutions for the equation 4x+6=4x+6

Mathematics
2 answers:
Andre45 [30]3 years ago
4 0

Answer:

All real numbers are possible solutions.

Step-by-step explanation:

4x + 6 = 4x + 6

~Subtract 6 to both sides

4x = 4x

~Subtract 4x to both sides

0 = 0

Best of Luck!

Lerok [7]3 years ago
3 0
1 I think not too sure tho
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Find two consecutive integers whose sum is 91
lys-0071 [83]
46+45=91 
Hope this helps!
6 0
3 years ago
Solve 6[4x(72-63)divided3]
GREYUIT [131]
Parentheses first, 72-63 is 9 next multiply by 4 which is 36 the you’ll divide by 3 now you have 12 so multiply that by 6 and you get 72. Just a hint, another way to write that without using the multiply or the divided would be 6[4(72-63)/3] but either way you want is fine. Hope this helped :)
3 0
3 years ago
Find an explicit solution of the given initial-value problem. (1 + x4) dy + x(1 + 4y2) dx = 0, y(1) = 0
MissTica

Answer:

a solution is 1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

Step-by-step explanation:

for the equation

(1 + x⁴) dy + x*(1 + 4y²) dx = 0

(1 + x⁴) dy  = - x*(1 + 4y²) dx

[1/(1 + 4y²)] dy = [-x/(1 + x⁴)] dx

∫[1/(1 + 4y²)] dy = ∫[-x/(1 + x⁴)] dx

now to solve each integral

I₁= ∫[1/(1 + 4y²)] dy = 1/2 *tan⁻¹ (2*y) + C₁

I₂=  ∫[-x/(1 + x⁴)] dx

for u= x² → du=x*dx

I₂=  ∫[-x/(1 + x⁴)] dx = -∫[1/(1 + u² )] du = - tan⁻¹ (u) +C₂ =  - tan⁻¹ (x²) +C₂

then

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) +C

for y(x=1) = 0

1/2 *tan⁻¹ (2*0) = - tan⁻¹ (1²) +C

since tan⁻¹ (1²) for π/4+ π*N and tan⁻¹ (0) for  π*N , we will choose for simplicity N=0 . hen an explicit solution would be

1/2 * 0 = - π/4 + C

C= π/4

therefore

1/2 *tan⁻¹ (2*y) = - tan⁻¹ (x²) + π/4

5 0
3 years ago
Solve with all work <br> −4(2 + 9) + 3 = 6 − 4( − 3)
ra1l [238]

Answer:

They do not equal eachother

Step-by-step explanation:

-4(2+9) + 3 = 6 - 4(-3)

-12 - 36 + 3 = 6 + 12

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3 0
3 years ago
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This is your perfect answer

7 0
3 years ago
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