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kondor19780726 [428]
2 years ago
8

I need help before with this before 12:00 am

Mathematics
2 answers:
bearhunter [10]2 years ago
8 0
7:18 light years hope you get it correct
frutty [35]2 years ago
6 0

Answer:

7.18 light-years

Step-by-step explanation:

6.8 x 10^13 = 68,000,000,000,000

9.46 x10 ^12 = 9,460,000,000,000

6.8 x 10^13  *  1 light year / 9.46 x 10^12 = 7.188 light years.

Have a Merry X-MAS Plz MArk Branilest

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Please help me thanks
BabaBlast [244]

Answer:

16.7

Step-by-step explanation:

We can use the Pythagorean theorem, a^2 + b^2 = c^2.

a = 11

c = 20

11^2 + b^2 = 20^2

121 + b^2 = 400

b^2 = 279

b = sqrt(279) = 16.7

5 0
3 years ago
(6^-8)^4
KIM [24]

Your Answer is A.

(-8) x 4

= -8 x 4

= -32

= 1/6 ^32


HOPE THIS HELPS!!

PLEASE MARK ME AS BRAINLIEST!!

5 0
3 years ago
IM DOING A TEST!<br><br> Idk how to do this help<br> Please try
goldenfox [79]

Answer:

1 is 102

2 is 78

~~~~~~~~~~~~~~~~~~~~

Always double check :)

7 0
3 years ago
Read 2 more answers
A circle is inscribed in a square. A point in the figure is selected at random. Find the probability that the point will be in t
hram777 [196]
P of selecting point on the shaded region   = shaded area/whole area 
<span>P( selecting point on the shaded ) = ( the four shaded circles ) / the whole square </span>
<span>P of  selecting point on the shaded  = ( 4 * ( π * r^2 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( 4 * ( π * (x/4)^2 ) )/ x^2 </span>
<span>P of  selecting point on the shaded  = ( 4 * ( π * x^2/16 ) )/ x^2 </span>
<span>P of  selecting point on the shaded = ( π * x^2/4 )/ x^2 </span>
<span>P of  selecting point on the shaded = x^2( π/4 )/ x^2 </span>
<span>P( selecting point on the shaded ) = π/4 ≈ 0.7854 ≈ 79%
 =80% 
D is right option hope this helps</span>
4 0
3 years ago
Which of the following is equivalent to (81m^6)^1/2?
ch4aika [34]
That would be option A 
because square root of 81 is 9 and square root m^6 is m^3.
3 0
3 years ago
Read 2 more answers
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