Answer:
First, I would check and see if she was correct. If she wasnt, I would simply show her why she was incorrect. If I was to accidently short her, I would give her the money and move on with my day. if she refused to leave after showing her that I gave her the correct amount of money, she would probably call for the manager. I'd get the manager, explain what happened, and the annoying customer would most likely get kicked out of the store.
(P.S: sorry if it was a little confusing lol)
Answer:
f = 4
Step-by-step explanation:
Step 1: Distribute
-11f = 7 - 14f + 5
Step 2: Combine like terms
-11f = 12 - 14f
Step 3: Add 14f to both sides
3f = 12
Step 4: Divide both sides by 3
f = 4
Algebraically, that will be expressed as:
Answer:
B, E
Step-by-step explanation:
The equation of that line in slope intercept form is y = -2/5x + 2
The slope of a line parallel to that line will be the same as its slope, so -2/5.
To find the y-intercept of a line that passes through the point (-5, 1) with that slope, you will have to plug in the x and y values of that point into what you know of the equation of the line.
y = -2/5x + b
1 = -2/5(-5) + b
1 = 2 + b
-1 = b
From this, you can construct an equation.
y = -2/5x - 1
However, this is not an answer choice.
It cannot be A because this line does not have a slope of -1.
2x + 5y = 15
5y = -2x - 5
y = -2/5x - 1
It can be B because this line is the same as the equation we came up with.
It cannot be C because this line does not have a slope of -1 or a y-intercept of -3.
2x + 5y = -15
5y = -2x - 15
y = -2/5x - 3
It cannot be D because this line does not have a y-intercept of -3.
y - 1 = -2/5(x + 5)
y - 1 = -2/5x - 2
y = -2/5x - 1
It can be E because this equation matches the one we came up with.
Answer:
d. 20
Step-by-step explanation:
To answer the question given, we will follow the steps below:
we need to first find p(3)
p(x) = x+ 7/ x-1
we will replace all x by 3 in the equation above
p(3) = 3+7 / 3-1
p(3) = 10/2
p(3) = 5
Similarly to find q(2)
q (x) = x^2 + x - 2,
we will replace x by 2 in the equation above
q (2) = 2^2 + 2 - 2
q (2) = 4 + 0
q (2) = 4
The product of p(3) and q(2) = 5 × 4 = 20