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4 years ago

Find the equation of the line that has a slope of 14 and passes through the point (-3,12).

Mathematics

1 answer:

Roman55 [17]4 years ago

8 0

Answer:

The answer is b=54

Step-by-step explanation:

y=mx+b

12=14(-3)+b

12=-42+b

54=b

hope that helps

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What numbers are 1.3 units from 0.4 on a number line?

Mashcka [7]

The numbers would be -0.9 and 1.7

3 0

4 years ago

Read 2 more answers

Hi can anyone answer this right ill give brainliest

olga_2 [115]

Answer:

The last one

Step-by-step explanation:

You start off with 50.

It says the water is being drained so the slope is negative.

6 0

3 years ago

Suppose the average yearly salary of an individual whose final degree is a master's is $43 thousand less than twice that of an

natka813 [3]

Answer:

A person who holds a master's degree would earn an average $63,000

A person who holds a bachelor's only would earn an average $53,000

Step-by-step explanation:

We will need to construct equations from the sentences.

Firstly, let the yearly average for a master's degree holder be m and that of bachelor's be b.

Now, we know that someone with a master's earn 43000 less than twice what someone with bachelors earn.

Mathematically,

m = 2b - 43,000

Combined, they have an average salary of 116,000

Mathematically,

m + b = 116,000

Now we have 2 equations to solve simultaneously.

m = 2b - 43,000 ......(i)

m + b = 116,000 .......(ii)

We can sub I into ii

2b - 43,000 + b = 116,000

2b+b = 116,000 + 43,000

3b = 159,000

b = 159,000/3 = 53,000

m = 2b - 43,000

m = 2(53,000) - 43,000 = 63,000

6 0

3 years ago

write the formula for absolute value function if its graph has the vertex at point (0,6) and passes through the point (-1,-2)

Readme [11.4K]

Answer:

First you need to find the slope of the line:

m=6-(-2) / (-1)-0 =-8

equation of line is:

y=mx+b

y=-8x+6

for absolute value function:

if x<0

y=-8x+6

if x>0

y=+8x-6

Step-by-step explanation:

8 0

2 years ago

Need help with inscribed angles If M

Bogdan [553]

Given:

In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and $m\angle BCD=30^\circ$ .

To find:

The $m\angle AOB$ .

Solution:

If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.

We have, DC is parallel to BA and BC is the transversal line.

$\angle OBA\cong \angle BCD$ [Alternate interior angles]

$m\angle OBA=m\angle BCD$

$m\angle OBA=30^\circ$

In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.

We know that base angles of an isosceles triangle are congruent.

$\angle OAB\cong \angle OBA$ [Base angles of an isosceles triangle]

$m\angle OAB=m\angle OBA$

$m\angle OAB=30^\circ$

In triangle AOB,

$m\angle OAB+m\angle OBA+m\angle AOB=180^\circ$

$30^\circ+30^\circ+m\angle AOB=180^\circ$

$60^\circ+m\angle AOB=180^\circ$

$m\angle AOB=180^\circ-60^\circ$

$m\angle AOB=120^\circ$

Therefore, the measure of angle AOB is 120 degrees.

6 0

3 years ago