Answer:
The answer is temperature
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B. An ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
<h3>When external ear squeeze occurs</h3>
External ear squeeze occurs when gas trapped in the external ear canal remains at atmospheric pressure while the external water pressure increases during descent.
Thus, we can conclude that, an ear squeeze occurs when the pressure inside the middle ear space is less than ambient (surrounding) pressure.
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Answer: 0.61
Explanation:
This is calculation based on friction.
Since the box rests on a flat surface, the force that exists between them is known as frictional force.
Since the friction is dynamic (velocity is not zero)
The frictional force = kinetic energy gained by the body.
Ff = 1/2mv^2
coefficient of kinetic friction × normal reaction = 1/2mv^2
Since normal reaction is equal to the weight(force acting along the vertical component)
Normal reaction= mg = 50 × 10 = 500N. Therefore,
coefficient of kinetic friction × 500 = 1/2×50×3.5^2
coefficient of kinetic friction = 50×3.5^2/1000
coefficient of kinetic friction= 0.61
We have that the Force is mathematically given as
F=170.833N
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</h3><h3>
Force </h3>
Question Parameters:
- The torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 41 N · m,
- the end of a 24 cm-long wrench to <em>loosen </em>the nut
Generally the equation for the Force is mathematically given as
Therefore
F=41/0.24
F=170.833N
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