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Andrej [43]
3 years ago
13

Which statement correctly describes the differences between positive and negative acceleration? Positive acceleration describes

a change in speed; negative acceleration describes no change in speed. Positive acceleration describes no change in speed; negative acceleration describes a change in speed. Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed. Positive acceleration describes a decrease in speed; negative acceleration describes an increase in speed.
Physics
2 answers:
salantis [7]3 years ago
7 0

Answer:

Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed.

Explanation:

Acceleration is defined as:

a=\frac{v-u}{\Delta t}

where

v is the final velocity

u is the initial velocity

\Delta t is the time taken for the change in velocity to occur

The value of \Delta t is always positive, so the sign of the acceleration depends on the numerator. More specifically, we have two situations:

- if v > u, then it means that the final velocity is greater than the initial velocity, so the acceleration is positive and the speed is increasing

- if v < u, then it means that the final velocity is smaller than the initial velocity, so the acceleration is negative and the speed is decreasing

qwelly [4]3 years ago
4 0

The correct answer is - Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed.

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the length of iron rod at 100 C is 300.36 cm and at 159 C is 300.54 cm.Calculate its length at 0 c and coefficient of linear exp
Ugo [173]

Answer:

The length at 0 °C is 300.05 cm

Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹

Explanation:

From the question given above, the following data were obtained:

Length (L₁) at 100 °C = 300.36 cm

Temperature 1 (θ₁) = 100 °C

Length (L₂) at 159 °C = 300.54 cm

Temperature 2 (θ₂) = 159 °C

Length (L₀) at 0 °C =?

Coefficient of linear expansion (α) =?

L₁ = L₀ (1 + θ₁α)

300.36 = L₀ (1 + 100α) ....(1)

L₂ = L₀ (1 + θ₂α)

300.54 = L₀ (1 + 159α) ..... (2)

Divide equation (2) by (1)

300.54 / 300.36 = L₀ (1 + 159α) / L₀ (1 + 100α)

1.0006 = (1 + 159α) / (1 + 100α)

Cross multiply

1.0006 (1 + 100α) = (1 + 159α)

1.0006 + 100.06α = 1 + 159α

Collect like terms

1.0006 – 1 = 159α – 100.06α

0.0006 = 58.94α

Divide both side by 58.94

α = 0.0006 / 58.94

α = 1.02×10¯⁵ C¯¹

Substitute the value of α into anything of the equation to obtain L₀. Here we shall use equation (2).

300.54 = L₀ (1 + 159α)

α = 1.02×10¯⁵ C¯¹

300.54 = L₀ (1 + 159 ×1.02×10¯⁵)

300.54 = L₀ (1 + 0.0016218)

300.54 = L₀ (1.0016218)

Divide both side by 1.0016

L₀ = 300.54 / 1.0016

L₀ = 300.05 cm

Summary:

The length at 0 °C is 300.05 cm

Coefficient of linear expansion of iron is 1.02×10¯⁵ C¯¹

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