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Andrej [43]
3 years ago
13

Which statement correctly describes the differences between positive and negative acceleration? Positive acceleration describes

a change in speed; negative acceleration describes no change in speed. Positive acceleration describes no change in speed; negative acceleration describes a change in speed. Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed. Positive acceleration describes a decrease in speed; negative acceleration describes an increase in speed.
Physics
2 answers:
salantis [7]3 years ago
7 0

Answer:

Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed.

Explanation:

Acceleration is defined as:

a=\frac{v-u}{\Delta t}

where

v is the final velocity

u is the initial velocity

\Delta t is the time taken for the change in velocity to occur

The value of \Delta t is always positive, so the sign of the acceleration depends on the numerator. More specifically, we have two situations:

- if v > u, then it means that the final velocity is greater than the initial velocity, so the acceleration is positive and the speed is increasing

- if v < u, then it means that the final velocity is smaller than the initial velocity, so the acceleration is negative and the speed is decreasing

qwelly [4]3 years ago
4 0

The correct answer is - Positive acceleration describes an increase in speed; negative acceleration describes a decrease in speed.

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A (20*20) cm² loop has a resistance of 0.10 Ω. A magnetic field perpendicular to the loop is B = 4t - 2t², where B is in tesla a
Ilya [14]

Answer with Explanation:

We are given that

Area of loop=(20\times 20) cm^2=400\times 10^{-4} m^2

1 cm^2=10^{-4} m^2

Resistance, R=0.1\Omega

B=4t-2t^2

We know that magnetic flux

\phi=BA

Emf ,E=\mid \frac{d\phi}{dt}\mid =\mid\frac{d(BA}{dt}\mid =\mid A\frac{dB}{dt}=400\times 10^{-4}\times \frac{4t-2t^2}{dt}\mid =\mid400\times 10^{-4}\times(4-4t)\mid

Current, I=\frac{E}{R}

Current, I=\frac{\mid 400\times 10^{-4}(4-4t)\mid }{0.1}=1.6\mid (1-t)\mid

Substitute t=0 s

Then, I=1.6\mid (1-0)\mid=1.6 A

Substitute t=1 s

Then, I=1.6\mid (1-1)\mid=0

Substitute

t=2 s

Current, I=1.6\mid(1-2)\mid=1.6 A

8 0
3 years ago
Read 2 more answers
16x^2y^2-25a^2b^2<br>factorize the expression​
SIZIF [17.4K]

Answer:

(4xy+5ab)(4xy-5ab)

Explanation:

16x^{2}y^{2}-25a^{2}b^{2}

4^2 is 16 and 5^2 is 25,

Also, (x-a)(x+a) = x^2-a^2

So, this factorized is:

(4xy+5ab)(4xy-5ab)

Hope this helps!

8 0
3 years ago
A thin uniform rod (length = 1.2 m, mass = 2.0 kg) is pivoted about a horizontal, frictionless pin through one end of the rod. (
Anika [276]

Answer:

a=9.8 rad/s^{2}

Explanation:

Torque, \tau is given by

\tau=Fr where F is force and r is perpendicular distance

R=0.5Lcos\theta where \theta is the angle of inclination

Torque, \tau can also be found by

\tau=Ia where I is moment of inertia and a is angular acceleration

Therefore, Fr=Ia and F=mg where m is mass and g is acceleration due to gravity

Making a the subject, a=\frac {Fr}{I}=\frac {mgr}{I} and already I is given as  

I=\frac {mL^{2}}{3} and r is 0.5Lcos\theta hence  

a=\frac {0.5mgLcos\theta}{1/3 mL^{2}}

a=\frac {3gcos\theta}{2L}

Taking g as 9.81, \theta is given as 37 and L is 1.2

a=\frac {3*9.81cos37}{2*1.2}=9.7932679419

a=9.8 rad/s^{2}

4 0
3 years ago
Robin Hood wishes to split an arrow already in the bull's-eye of a target 40 m away.
tamaranim1 [39]

Answer:

5.843 m

Explanation:

suppose that the arrow leave the bow with a horizontal speed , towards he bull's eye.

lets consider that horizontal motion

distance = speed * time

time = 40/ 37 = 1.081 s

arrow doesnot have a initial vertical velocity component. but it has a vertical motion due to gravity , which may cause a miss of the target.

applying motion equation

(assume g = 10 m/s²)

s=ut+\frac{1}{2}*gt^{2}  \\= 0+\frac{1}{2}*10*1.081^{2}\\= 5.843 m

Arrow misses the target by 5.843m ig the arrow us split horizontally

4 0
3 years ago
What is used to block the UV light during screen development process to create a stencil in the emulsion
coldgirl [10]

Answer:

Invisible UV energy reacts with emulsion sensitizer and hardens the stencil so it won't dissolve with water and rinse down the drain

Explanation:

4 0
2 years ago
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