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3 years ago

6

A pair of sneakers cost $45 now. What would be the cost of the sneakers in ten years if the inflation rate is 7%? Estimate your

answer to the nearest whole number.

1 answer:

Vika [28.1K]3 years ago

3 0

The inflation rate would increase the price of the sneakers to $88.52.

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2(r+5)-4(r-1)=32 what is the solution?

muminat

Answer:

2r+10-4r+4=32

-2r+14=32

-2r= 32-14

-2r=18

R= -9

Step-by-step explanation:

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24 packs of lemonade 2 for $9 12 packs 4 for $10 12 packs 3 for $9 for each store what is the ratio of the number of cans to the

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12 × 10 (48Cans) = 10:48
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What is the solution of the system of equations shown in the graph below?

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Step-by-step explanation:

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3 years ago

Identify the slope and y-intercept of the<br> equation 2x + 5y = 20

DIA [1.3K]

Answer:

Slope = - ⅖

Y-intercept = (0, 4), where <em>b</em> = 4

Step-by-step explanation:

Given the linear equation in standard form, 2x + 5y = 20, where A = 2, B = 5, and C = 20:

Start by transforming the standard equation into its slope-intercept form, y = mx + b, where <em>m</em> = slope, and <em>b</em> = y-intercept.

Subtract 2x from both sides:

2x -2x + 5y = - 2x + 20

5y = -2x + 20

Divide both sides by 5 to isolate y:

$\frac{5y}{5} = \frac{-2x + 20}{5}$

y = - ⅖x + 4 ⇒ This is the slope-intercept form where the <u>slope</u>,<em> </em><em><u>m</u></em><u> = -⅖</u>, and the y-intercept,<em> b</em> = 4. The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, <em>b</em>). The y-coordinate is the value of <em>b </em>in the slope-intercept form. Therefore, the <u>y-intercept</u> is (0, 4).

3 0

3 years ago

In a chemical plant, 24 holding tanks are used for final product storage. Four tanks are selected at random and without replacem

Damm [24]

Answer:

a) P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) = 0,7120 or 71,2 %

c) P(C) = 0,2055 or P(C) = 20,55 %

Step-by-step explanation:

We will use two concepts in solving this problem.

1.- The probability of an event (A) is for definition:

P(A) = Number of favorable events/ Total number of events FE/TE

2.- If A and B are complementary events ( the sum of them is equal to 1) then:

P(A) = 1 - P(B)

a) The total number of events is:

C ( 24,4) = 24! / 4! ( 24 - 4 )! ⇒ C ( 24,4) = 24! / 4! * 20!

C ( 24,4) = 24*23*22*21*20! / 4! * 20!

C ( 24,4) = 24*23*22*21/4*3*2

C ( 24,4) = 24*23*22*21/4*3*2 ⇒ C ( 24,4) = 10626

TE = 10626

Splitting the group of tanks in two 6 with h-v and 24-6 (18) without h-v

we get that total number of favorable events is the product of:

FE = 6* C ( 18, 3) = 6 * 18! / 3!*15! = 18*17*16*15!/15!

FE = 4896

Then P(A) ( 1 tank in the sample contains h-v material is:

P(A) = 4896/10626

P(A) = 0,4607 or P(A) = 46,07 %

b) P(B) will be the probability of at least 1 tank contains h-v

P(B) = 1 - P ( no one tank with h-v)

Again Total number of events is 10626

The total number of favorable events for the ocurrence of P is C (18,4)

FE = C (18,4) = 18! / 14!*4! = 18*17*16*15*14!/14!*4!

FE = 18*17*16*15/4*3*2 = 3060

Then P = 3060/10626

P = 0,2879

And the probability we are looking for is

P(B) = 1 - 0,2879

P(B) = 0,7120 or 71,2 %

c) We call P(C) the probability of finding exactly 1 tank with h-v and t-i

having 4 with t-i tanks is:

reasoning the same way but now having 4 with t-i (impurities) number of favorable events is:

FE = 6*4* C(14,2) = 24 * 14!/12!*2!

FE = 24* 14*13*12! / 12!*2

FE = 24*14*13/2 ⇒ FE = 2184

And again as the TE = 10626

P(C) = 2184/ 10626

P(C) = 0,2055 or P(C) = 20,55 %

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4 years ago