Answer:
-149
Step-by-step explanation:
=-11 + (n - 1)(-3)
by observation
when n = 0, 
= 1st term
when n = 1, 
= 2nd term
.....
when n = x, 
= (x+1)th term
hence if we want to find the 48th term, n = 48 - 1 = 47
when n = 47, 
= 48th term
= -11 + (47-1)(-3)
= -11 + 46(-3)
= - 11 - 138
= -149
![(x+5)(x-3)[x-(4-i)][x-(4+i)] \\ (x^{2}+5x-3x-15)(x-4+i)(x-4-i) \\ (x^{2}+5x-3x-15)(x^{2} -4x-xi-4x+16+4i+xi-4i- i^{2} ) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16- i^{2}) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16-(-1)) \\ (x^{2}+5x-3x-15)( x^{2} -8x+16+1) \\ (x^{2}+5x-3x-15)( x^{2} -8x+17)](https://tex.z-dn.net/?f=%28x%2B5%29%28x-3%29%5Bx-%284-i%29%5D%5Bx-%284%2Bi%29%5D%0A%20%5C%5C%20%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28x-4%2Bi%29%28x-4-i%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28x%5E%7B2%7D%20-4x-xi-4x%2B16%2B4i%2Bxi-4i-%20i%5E%7B2%7D%20%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16-%20i%5E%7B2%7D%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16-%28-1%29%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B16%2B1%29%0A%5C%5C%0A%28x%5E%7B2%7D%2B5x-3x-15%29%28%20x%5E%7B2%7D%20-8x%2B17%29)
From there just distribute and simplify.
Answer:
true
Step-by-step explanation:
Answer:
AG = 16
Step-by-step explanation:
If you have a parallelogram, then the diagonals are bisected, meaning GS and SA are congruent, same with OS and ST. So, because 8 + 8 = 16, the length of AG = 16.
