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3 years ago

Which inequality is shown?

Mathematics

1 answer:

Nimfa-mama [501]3 years ago

5 0

Answer:

It should be J

Step-by-step explanation:

The line is solid indicating it is a greater than/less than/equal relationship and the shaded area indicated a positive y (so greater than)

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What is the area of the object above?

valina [46]

Your answer is 104 square inches because you have to find the area of the top rectangle by multiplying 12 x 7, then find the area of the bottom square by multiplying 5 x 4, and then add both answers together which equals 104 square centimeters ;)

7 0

3 years ago

Helpppp with this :>

Paul [167]

Answer:

x=9

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Carter's telephone bill is automatically deducting $48 from his bank account every month. How much will the deductions total for

vivado [14]

Answer:576

Step-by-step explanation: For every year, Carter’s telephone bill will be $576. This is because is we know how much he is charged a month, we can take that number and multiply it by 12. We are multiplying it by 12 because there are 12 months in 1 year. Once we multiplied it that’s how we find out the cost for 1 year.

Have a great day,

Eric

6 0

3 years ago

Suppose n(U) = 150, n(A) = 35, and n(B) = 89.<br> (a) If n(A U B) = 90, find n(A n B).

avanturin [10]

Answer:

first of all use formula:

n(AUB)=n(A)+n(B)-n(AnB)

4 0

3 years ago

A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran

Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0

3 years ago