Question

At what temperature would the volume of a gas be equal to 45.7 L, if the volume of that gas was 33.9 L at 12.4ºC? 241.9 K 241.9 K 451.2 K 451.2 K 384.7 K 384.7 K 273.15 K

Answer 1

Answer:

The temperature will be 384.7 K

Explanation:

Charles's Law consists of the relationship that exists between the volume and the temperature of a certain quantity of ideal gas, which is maintained at a constant pressure, by means of a constant of proportionality that is applied directly. For a given sum of gas at a constant pressure, as the temperature increases, the volume of the gas increases and as the temperature decreases, the volume of the gas decreases because the temperature is directly related to the energy of the movement of the gas molecules. .

In summary, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the quotient that exists between the volume and the temperature will always have the same value:

$\frac{V}{T} =k$

Having an initial state 1 and a final state 2, the following is true:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case:

• V1= 33.9 L
• T1= 12.4 C= 285.4 K (being 0 C= 273 K)
• V2= 45.7 L
• T2= ?

Replacing:

$\frac{33.9 L}{285.4 K} =\frac{45.7 L}{T2}$

Solving:

$T2=45.7 L*\frac{285.4 K}{33.9 L}$

T2= 384.7 K

The temperature will be 384.7 K