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rosijanka [135]
3 years ago
6

Which is a chemical property that can be used to identify hydrogen peroxide? A. clear and colorless B. reacts when its exposed t

o light C. boiling point of 108 °C (226.4 °F) D. melting point of -33 °C (–27.4 °F)
Chemistry
2 answers:
nordsb [41]3 years ago
7 0

Answer: Option (B) is the correct answer.

Explanation:

A property which tends to bring changes in chemical composition of a substance is known as chemical property.

For example, precipitation, reactivity, toxicity etc are chemical property.

So, when hydrogen peroxide reacts upon exposure to light then it depicts its chemical property.

On the other hand, a property that does not bring any change in chemical composition of a substance are known as physical properties.

For example, shape, size, mass, volume, density, etc of a substance are all physical properties.

Thus, we can conclude that a chemical property that can be used to identify hydrogen peroxide is that it reacts when its exposed to light.

ziro4ka [17]3 years ago
3 0
B. reacts when its exposed to light
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The 12L helium tank pressurized to 160 atm will fill <em>636 </em>3-liter balloons

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It is possible to answer this question using Boyle's law:

P_1V_1=P_2V_2

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1920L - 12L = 1908L

1908L will fill:

1908L×\frac{1balloon}{3L} = <em>636 balloons</em>

<em></em>

I hope it helps!

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4 years ago
The length of a path between two points
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Displacement is the direction from the starting point and the length of a directly line from the starting point to the ending point.

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Explanation:

The given reaction is:

B2O3 (s) + 3C (s) + 3Cl2 (g) \rightarrow 2BCl3 (g) + 3CO (g)

In order to identify the limiting reagent calculate the moles of B2O3, C and Cl2. The reagent with the lowest moles is the limiting reactant

Moles(B2O3)=\frac{Mass(B2O3)}{Mol.wt(B2O3)}=\frac{139g}{69.6g/mol}=1.997moles

Moles(C)=\frac{Mass(C)}{At.wt(C)}=\frac{87.8g}{12g/mol}=7.317moles

Moles(Cl2)=\frac{Mass(Cl2)}{Mol.wt(Cl2)}=\frac{650g}{70.9g/mol}=9.168moles

Since the moles of B2O3 < C < Cl2, the limiting reactant is B2O3

Based on the reaction stoichiometry:

1 mole of B2O3 produces 2 moles of BCl3

Hence, the number of moles of BCl3 produced under the experimental conditions = 2*1.997=3.994 moles

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8 0
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Answer:

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I have 4 moles of oxygen, so now it is my excess.

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