Answer:
Crossing two chickens heterozygous for the trait feather color, when brown feathers are dominant over red feathers, will produce offspring with brown and red feathers in a brown:red phenotypic ratio of 3:1.
Explanation:
Knowing that in chickens brown feathers are the expression of the dominant allele (B) and the recessive allele is red (b), crossing two heterozygous individuals (Bb) will result in offspring that are likely to have brown or red feathers.
The cross can be represented by a Punnett Square:
<u>Bb X Bb cross
</u>
alleles B b
B BB Bb
b Bb bb
Where the result is:
<u>Genotypes</u>:
<u>Phenotypes</u>:
- Brown feathers, 75%
- Red feathers, 25%.
In this case, the probability of having brown or red feathers is 3:1.
Workout equipment such as, pull-up bars, a track, and weights.
Answer:
The Yellowstone nourishment web given shows that voles and mice subject to grasses and herbs. The badger rely upon the two voles and mice. This perception can be induced as that voles can keep up bigger populace when they exist with mice. This is on the grounds that the badgers prey both on mice and voles yet not the only one on voles. Thus, the mice can likewise keep up a steady populace on coexisting with voles as there is equivalent open door for mice and voles be implored up on by badgers. The badgers can keep up a steady populace when they rely upon the two mice and voles for their nourishment. In this manner, the alternatives a,b
Comets are most like planets have elliptical orbits
1) To calculate the population density you first need to know how many <span>squirrels form that population.
To calculate the number of</span><span> squirrels:
1500</span> squirrels is the capacity, so it's equivalent to 100%
So how much squirrels are present in 80% of the area:
1500----100 %
x----------80 %
x= 1200 <span>squirrels
</span>
2)Population Density equals the number of squirrels divided by the land area
In the first part was calculated the number of squirrels and the exercise gives us the area in hectares so the only thing left to do is divide them.
(since this exercise doesn't specify that the area needs to be in a certain measurement we can use hectares)
Population Density = 1200/ 150
<span>The population density of the squirrels is 8 per hectare</span>
