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skelet666 [1.2K]
3 years ago
9

PLEASE HELP ASAP

Mathematics
2 answers:
Nastasia [14]3 years ago
7 0

Answer:

The measure of angle BCA = The measure of angle C prime A prime B prime

Step-by-step explanation:

slavikrds [6]3 years ago
4 0
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The college hiking club is having a fund raiser to buy new equipment for fall and winter outings. The club is selling Chinese fo
PolarNik [594]

Answer:

a)

- the probability she will win the dinner for two is 0.016

- the probability she will not win the dinner for two is 0.984

b)

- Lisa's expected earnings is $0.57

- Money she effectively contributed to the hiking club is $11.43

Step-by-step explanation:

Given the data in the question;

fortune cookies; $1 per cookies

club sold 743

a) Lisa bought 12 cookies. What is the probability she will win the dinner for two?

P( she will win ) = Number of cookies bought / Total number of cookies

P( she will win ) = 12 / 743

P( she will win ) = 0.01615 ≈ 0.016

Therefore,  the probability she will win the dinner for two is 0.016

P( she will not win ) = 1 - P( she will win )

P( she will not win ) = 1 - 0.016

P( she will not win ) = 0.984

Therefore,  the probability she will not win the dinner for two is 0.984

b)  Lisa's expected earnings can be found by multiplying the value of the dinner by the probability that she will win. What are Lisa's expected earnings? (Round your answer to two decimal places.)$

given that value of dinner = $35

P( she will win ) = 0.01615

so

Lisa's earning = $35 × 0.01615

Lisa's earning = $0.57

Therefore, Lisa's expected earnings is $0.57

- How much did she effectively contribute to the hiking club? (Round your answer to two decimal places.)$

Lisa's contribution = Money she paid for cookies - money from expected earnings

Lisa's contribution = ( 12 × $1 ) -  $ 0.57

Lisa's contribution = $12 -  $0.57

Lisa's contribution = $11.43

Therefore, Money she effectively contributed to the hiking club is $11.43

4 0
3 years ago
Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh
yuradex [85]

Answer:

The northern lighthouse is approximately 24.4\; \rm mi closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as \rm N, the southern lighthouse as \rm S, and the boat as \rm B. These three points would form a triangle.

It is given that two of the angles of this triangle measure 40^{\circ} (northern lighthouse, \angle {\rm N}) and 21^{\circ} (southern lighthouse \angle {\rm S}), respectively. The three angles of any triangle add up to 180^{\circ}. Therefore, the third angle of this triangle would measure 180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ} (boat \angle {\rm B}.)

It is also given that the length between the two lighthouses (length of \rm NS) is 75\; \rm mi.

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, \angle {\rm B} is opposite to side \rm NS, whereas \angle {\rm S} is opposite to side {\rm NB}. Therefore:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}.

Substitute in the known measurements:

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}.

Rearrange and solve for the length of \rm NB:

\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}.

(Round to at least one more decimal places than the values in the choices.)

Likewise, with \angle {\rm N} is opposite to side {\rm SB}, the following would also hold:

\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}.

\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}.

\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}.

In other words, the distance between the northern lighthouse and the boat is approximately 30.73\; \rm mi, whereas the distance between the southern lighthouse and the boat is approximately 55.12\; \rm mi. Hence the conclusion.

4 0
3 years ago
5.3.24 A is a 3times3 matrix with two eigenvalues. Each eigenspace is​ one-dimensional. Is A​ diagonalizable? Why? Select the co
abruzzese [7]

Answer:

C. No. The sum of the dimensions of the eigenspaces equals nothing and the matrix has 3 columns. The sum of the dimensions of the eigenspace and the number of columns must be equal.

Step-by-step explanation:

Here the sum of dimensions of eigenspace is not equal to the number of columns, so therefore A is not diagonalizable.

5 0
3 years ago
Solve for x <br> x(6x+1)= 2
Montano1993 [528]

Answer:

x=1/2,-2/3

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0
3 years ago
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