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Anarel [89]
3 years ago
15

What is the solution of this system of linear equations?y=3x-2 y-2=x

Mathematics
2 answers:
victus00 [196]3 years ago
5 0
Your answer would be -8
eduard3 years ago
4 0

Answer:

(2,4)

Step-by-step explanation:

because 2 times 4 would equal 8

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Paolo is using his grandmother's breakfast bar recipe. He always doubles
Papessa [141]

Answer:

6\frac{1}{3} = 2\frac{1}{2} * 2 + \frac{x}{2}

Step-by-step explanation:

lets start with what we know.

the recipe calls for 2 \frac{1}{2} cups of yogurt. and Paolo doubles the recipe. so multiply the recipe for yogurt by 2

2 \frac{1}{2} * 2 = 5 cups of yogurt.

the total of yogurt and oats is 6\frac{1}{3} and we know how much yogurt we have so we subtract that from the total of both.

6\frac{1}{3} - 5 = 1\frac{1}{3}

the oats after doubling were 1\frac{1}{3} cups so u divide it by 2

1\frac{1}{3} / 2 = \frac{2}{3} before doubling

7 0
2 years ago
Find the Y-coordinate of point P that lies 1/3 along segment RS, where R (-7, -2) and S (2, 4).
QveST [7]

Solution:

Given that the point P lies 1/3 along the segment RS as shown below:

To find the y coordinate of the point P, since the point P lies on 1/3 along the segment RS, we have

\begin{gathered} RP:PS \\ \Rightarrow\frac{1}{3}:\frac{2}{3} \\ thus,\text{ we have} \\ 1:2 \end{gathered}

Using the section formula expressed as

[\frac{mx_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}]

In this case,

\begin{gathered} m=1 \\ n=2 \end{gathered}

where

\begin{gathered} x_1=-7 \\ y_1=-2 \\ x_2=2 \\ y_2=4 \end{gathered}

Thus, by substitution, we have

\begin{gathered} [\frac{1(2)+2(-7)}{1+2},\frac{1(4)+2(-2)}{1+2}] \\ \Rightarrow[\frac{2-14}{3},\frac{4-4}{3}] \\ =[-4,\text{ 0\rbrack} \end{gathered}

Hence, the y-coordinate of the point P is

0

8 0
1 year ago
If f={(0,2),(2,6),(3,5),(4,9)} what is f^(-1)(9)
tangare [24]

Answer is 9 f-^1

I hope this correct :D

7 0
3 years ago
Two accounts earn simple interest. The balance y (in dollars) of Account A after x years can be modeled by y=10x 500. Account B
12345 [234]
In an installment loan, a lender loans a borrower a principal amount P, on which the borrower will pay a yearly interest rate of i (as a fraction, e.g. a rate of 6% would correspond to i=0.06) for n years. The borrower pays a fixed amount M to the lender q times per year. At the end of the n years, the last payment by the borrower pays off the loan.

After k payments, the amount A still owed is

<span>A = P(1+[i/q])k - Mq([1+(i/q)]k-1)/i, = (P-Mq/i)(1+[i/q])k + Mq/i. </span>The amount of the fixed payment is determined by<span>M = Pi/[q(1-[1+(i/q)]-nq)]. </span>The amount of principal that can be paid off in n years is<span>P = M(1-[1+(i/q)]-nq)q/i. </span>The number of years needed to pay off the loan isn = -log(1-[Pi/(Mq)])/(q log[1+(i/q)]). The total amount paid by the borrower is Mnq, and the total amount of interest paid is<span>I = Mnq - P.</span>
3 0
2 years ago
PLEASE HELP ME WITH THIS
Harrizon [31]

Answer:

The last option.

Step-by-step explanation:

Hope this helps!

Wait hold on

6 0
3 years ago
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