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GarryVolchara [31]
3 years ago
12

A fur pillow costs $50 and sells for $80. What is the rate of markup based on the selling price?

Mathematics
1 answer:
eimsori [14]3 years ago
6 0
The markup based in the price will be 246
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Find the height of a square pyramid that has a volume of 75 cubic feet and a base length of 5 feet.
Rudiy27

Answer:

9 ft

Step-by-step explanation:

Let's begin with the formula for the volume of a square pyramid.  If s is the base length, then the area of the base is s^2.  The volume of the pyramid is then V = (1/3)(base area)(height).  We know the volume and the base length (s), and want to find the height.  Solving V = (1/3)(base area)(height)

for height, we get:

3V = (base area)(height), or

    3V

---------------- = height

base area

Substituting 75 ft^3 for V and (5 ft)^2 for base area, we get:

               3(75 ft^3)              9 ft

height = ------------------ = ----------------- = 9 ft

                 25 ft^2                   1

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3 years ago
True or false stats question
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Answer:

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The slope is negative. The relationship is proportional

Step-by-step explanation:

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Kerri ran the same distance in four different races. Her times were 18.04 seconds, 21.39 seconds, 12.99 seconds, and 14.14 secon
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A,B and C are the vertices of one triangle.
dsp73

Answer:


Step-by-step explanation:

Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.

To prove: DE is parallel to BC.

Construction: Join DE.

Proof: If we prove the basic proportionality theorem that is \frac{AD}{DB}=\frac{AE}{EC}, then it proves that DE is parallel to BC.

Now, Mid Point D has coordinates=(\frac{4+2}{2},\frac{6-2}{2})=(3,2) and Mid Point E has coordinates=(\frac{4-2}{2},\frac{6-4}{2})=(1,1)

Now, AD= \sqrt{(4-3)^{2}+(6-2)^{2}}=\sqrt{17}

DB=\sqrt{(3-2)^{2}+(2+2)^{2}}=\sqrt{17}

AE=\sqrt{(4-1)^{2}+(6-1)^{2}}=\sqrt{34}

EC=\sqrt{(1+2)^{2}+(1+4)^{2}}=\sqrt{34}

Now, \frac{AD}{DB}=\frac{AE}{EC}

=\frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{34}}{\sqrt{34}}=\frac{1}{1}

Hence, \frac{AD}{DB}=\frac{AE}{EC}

Thus, By basic proportionality theorem, DE is parallel to BC.

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