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alexira [117]
3 years ago
15

a classroom is arranged with 10 seats in the front row 12 seats in the middle row and 18 seats in the back row the teacher rando

mly assigned seats to students as they enter the classroom what is the probability of the first student who enter the classroom will be assigned a seat in the middle row?​
Mathematics
1 answer:
myrzilka [38]3 years ago
8 0

Answer:

3/10

Step-by-step explanation:

12/40 = 3/10

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Vanessa uses the expressions (3x2 + 5x + 10) and (x2 – 3x – 1) to represent the length and width of her patio. Which expression
Brut [27]

The area of rectangle with length l and width w is

A=l\cdot w.

If the length of rectangle is expressed as l=3x^2 + 5x + 10 and the width of rectangle is expressed as w=x^2-3x-1, then the area of rectangle is

A=(3x^2 + 5x + 10)(x^2-3x-1)=3x^4-4x^3-8x^2-35x-10.

8 0
3 years ago
Read 2 more answers
Which of the following sets of ordered pairs is a function?
svetlana [45]

Answer:

it would be D

Step-by-step explanation:

all other choices have a repeating x value.

7 0
3 years ago
If $8259 principal is invested in a savings account that pays 5.25% interest compounded continuously how much money will be in t
VMariaS [17]

Answer:

A(10) = $13,961.50

Step-by-step explanation:

First, convert R as a percent to r as a decimal

r = R/100

r = 5.25/100

r = 0.0525 rate per year,

Then solve the equation for A

The formula is given as:

A = Pe^rt

P = 8259

r = 0.0525

t = 10 years.

Hence,

A = 8,259.00 × e^(0.0525×10)

A = $13,961.50

Therefore, the money that will be in the account after 10 years is $13,961.50

5 0
3 years ago
What is the circumference of a circle with the radius of 5 cm
Citrus2011 [14]
C=pi(radius)^2
c=pi(5)^2
c=pi(25)
c=78.5398163397...
c is about 78.5

4 0
3 years ago
a port and a radar station are 2 mi apart on a straight shore running east and west. a ship leaves the port at noon traveling no
Rom4ik [11]

Answer:

The rate of change of the tracking angle is 0.05599 rad/sec

Step-by-step explanation:

Here the ship is traveling at 15 mi/hr north east and

Port to Radar station = 2 miles

Distance traveled by the ship in 30 minutes = 0.5 * 15 = 7.5 miles

Therefore the ship, port and radar makes a triangle with sides

2, 7.5 and x

The value of x is gotten from cosine rule as follows

x² = 2² + 7.5² - 2*2*7.5*cos(45) = 39.04

x = 6.25 miles

By sine rule we have

\frac{sin A}{a} = \frac{sin B}{b}

Therefore,

\frac{sin 45}{6.25} = \frac{sin \alpha }{7.5}

α = Angle between radar and ship α

∴ α = 58.052

Where we put

\frac{sin 45}{6.25} = \frac{sin \alpha }{x} to get

\frac{x}{6.25} = \frac{sin \alpha }{sin 45} and differentiate to get

\frac{\frac{dx}{dt} }{6.25} = cos\alpha\frac{\frac{d\alpha }{dt}  }{sin 45}

\frac{15sin45 }{6.25cos\alpha } =\frac{d\alpha }{dt}  }= 3.208 degrees/second = 0.05599 rad/sec.

6 0
3 years ago
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