<em>Depending on what you trying to say...
</em>
Six times a length (w) is 6w
or
Six times a length is w, is 6l=w
<em>But I can't tell because of the typo
</em>
Hope this helps!
Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
<em />
You're looking for a solution of the form
where
and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:
Then
The general solution to the ODE is
which simplifies somewhat to
Answer:
1; 3; 9; 27, 81
-15; -8; -1; 6; 13
1/2; 1/4; 1/8; 1/16; 1/32
Step-by-step explanation:
Hope This Helps!
Thanks For the 5 points ; )
Answer:
Step-by-step explanation:
Here, x represents the number of tickets and y represents the number of T-shirts.
As per the statement:
Each ticket costs $25, and souvenir T-shirts are $12 each
⇒Total cost of ticket = 25x and Total cost for T-shirt = 12y
It is also given that there is a $4 service fee for the entire purchase.
Since, she has $130
⇒
Therefore, an inequality could you use to answer the problem is,
Hi there
The formula is
A=p (1+r)^t
A future value
P present value 75
R interest rate 0.05
T time
After 1 year the balance is
A=75×(1+0.05)
A=78.75
After 2 years
A=75×(1+0.05)^(2)
A=82.69
After 5 years
A=75×(1+0.05)^(5)
A=95.72
After 20 years
A=75×(1+0.05)^(20)
A=198.99 round
A=199
Hope it helps