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gulaghasi [49]
3 years ago
11

Find the square of 2a plus 3b​

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Here is your answer!!

andriy [413]3 years ago
6 0

Answer:

= 4a^{2} + 12ab + 9b^{2}.

Step-by-step explanation:

(2a+3b)^{2}

= (2a + 3b) (2a + 3b)

= 4a^{2} + 6ab + 6ab + 9b^{2}

= 4a^{2} + 12ab + 9b^{2}.

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WILL MARK BRAINLIEST
Lubov Fominskaja [6]

Answer:

the answer is 2: one pair of sides is parallel and the other pair is congruent.

Step-by-step explanation:

6 0
3 years ago
Express the complex number in trigonometric form. -6 + 6 square root of 3 i ?
bagirrra123 [75]
\bf \begin{array}{clclll}
-6&+&6\sqrt{3}\ i\\
\uparrow &&\uparrow \\
a&&b
\end{array}\qquad 
\begin{cases}
r=\sqrt{a^2+b^2}\\
\theta =tan^{-1}\left( \frac{b}{a} \right)
\end{cases}\qquad r[cos(\theta )+i\ sin(\theta )]\\\\
-------------------------------\\\\

\bf r=\sqrt{(-6)^2+(6\sqrt{3})^2}\implies r=\sqrt{36+(6^2\cdot 3)}\implies r=\sqrt{144}
\\\\\\
r=12\leftarrow 
\\\\\\
\theta =tan^{-1}\left( \frac{6\sqrt{3}}{-6} \right)\implies \theta =tan^{-1}\left( -\sqrt{3}\right)\implies \theta =
\begin{cases}
\frac{2\pi }{3}\leftarrow \\
\frac{5\pi }{3}
\end{cases}

now, notice, there are two valid angles for such a tangent, however, if we look at the complex pair, the "a" is negative and the "b" is positive, that means, "x" is negative and "y" is positive, and that only occurs in the 2nd quadrant, so the angle is in the second quadrant, not on the fourth quadrant.

thus         \bf 12\left[cos\left( \frac{2\pi }{3} \right) +i\ sin\left( \frac{2\pi }{3} \right) \right]
5 0
3 years ago
Solve for the given time.
LenaWriter [7]

Answer:

8851.86

Step-by-step explanation:

100-4.3= 95.7%

15000(.957)^12

5 0
3 years ago
What is the value of x?
andrew11 [14]
Hope this will help you .

answer is 68

given than 2 sides are equal therefor 2 angles are also equal ,

so, angle 1 + angle2 + angleX = 180 [ASP]

2angle1 + angle X = 180
angle x = 150 - [56][2]
angle x = 180-112

ANGLE x = 68 DEGREE
MARK IT BRAINIEST IF IT WAS REALLY HELPFUL.
4 0
3 years ago
Need some help please
Gnoma [55]
You can use this to help you. label the triangle like the picture and use the equations. I hope this helps.

3 0
3 years ago
Read 2 more answers
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