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kaheart [24]
3 years ago
6

0.6w = 0.48 how u do this

Mathematics
2 answers:
Lelechka [254]3 years ago
4 0
0.6w = 0.48 You need to find what times 6 equals 48, add a decimal in front of it and violá.
vovangra [49]3 years ago
3 0

A variable next to any number means to multiply, so we would do the inverse operation -- We would divide 0.48 by 0.6, which is 0.8. Therefore, W=0.48. To check your work, multiply 0.6 by 0.8, and what do you know? It's 0.48! :)
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Select the correct answer. x Probability 0 0.2 1 0.1 2 0.4 3 0.2 4 0.1 The probability distribution of x, a discrete random vari
Alex_Xolod [135]

Answer: The option B. 1.9 is correct

Explanation:

We are given the below information:

x               Probability P(x)

0                      0.2

1                       0.1

2                      0.4

3                       0.2

4                       0.1

The expected value of x is given below:

E(x)=\sum x P(x)

         =(0 \times 0.2)+(1 \times 0.1)+(2 \times 0.4)+(3 \times 0.2)+(4 \times 0.1)

        =0+0.1+0.8+0.6+0.4

        =1.9

Therefore, the expected value of x is 1.9      



7 0
3 years ago
HELP IM TIMED!(giving 50 points)
lutik1710 [3]

Answer:

A and D and E

Step-by-step explanation:

Substitute the variable(in this case) <em>t</em> for 3, then use the order of operations to simplify(PEMDAS), which will give you 33 for both expressions. To see if two expressions are equivalent, you need to substitute the variable for an odd number AND an even number, so next, substitute the variable <em>t </em>for the number 6, which will give you 51 for both expressions. That means the expressions are equivalent

Hope this helps :)

P.S. Mark brainliest pls

6 0
3 years ago
Read 2 more answers
What what is the standard and expanded form of 3 billion 630 2900058
algol [13]
3,000,000,000,000+600,000,000+30,000,000+200,000+90,000+50+8
3 0
3 years ago
Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam
tigry1 [53]

Answer:

P(A) = \frac{30}{100}

P(B) = \frac{77}{100}

P(A\ n\ B) = \frac{22}{100}

P(A\ u\ B) = \frac{85}{100}

Step-by-step explanation:

Given

See attachment for proper format of table

n = 100 --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

Yes = 22 and No = 8

So, we have:

n(A) = Yes + No

n(A) = 22 + 8

n(A) = 30

P(A) is then calculated as:

P(A) = \frac{n(A)}{Sample}

P(A) = \frac{30}{100}

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

(1) = 22    (2) = 25 and (3) = 30

So, we have:

n(B) = (1) + (2) + (3)

n(B) = 22 + 25 + 30

n(B) = 77

P(B) is then calculated as:

P(B) = \frac{n(B)}{Sample}

P(B) = \frac{77}{100}

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

n(A\ n\ B) = 22

The probability is then calculated as:

P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}

P(A\ n\ B) = \frac{22}{100}

Solving (d): P(A u B)

This is calculated as:

P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)

This gives:

P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}

Take LCM

P(A\ u\ B) = \frac{30+77-22}{100}

P(A\ u\ B) = \frac{85}{100}

8 0
3 years ago
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$646 I think.. Hopefully this is right.
6 0
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