Using the Pythagorean theorem a^2 + b^2 = c^2
where a and b are the legs and c is the hypotenuse
so a = 6 and c = 8
lets solve for b
6^2 + b^2 = 8^2
36 + b^2 = 64
b^2 = 64 - 36
b^2 = 28
b = sqrt(28)
b = 5.29
b = 5.3 yards
We obtain the joint PMF directly from the joint MGF:

![\implies\mathrm{Pr}[X=x,Y=y]=\begin{cases}0.1&\text{for }x=y=0\\0.2&\text{for }x=1,y=0\\0.3&\text{for }x=0,y=1\\0.4&\text{for }x=y=1\\0&\text{otherwise}\end{cases}](https://tex.z-dn.net/?f=%5Cimplies%5Cmathrm%7BPr%7D%5BX%3Dx%2CY%3Dy%5D%3D%5Cbegin%7Bcases%7D0.1%26%5Ctext%7Bfor%20%7Dx%3Dy%3D0%5C%5C0.2%26%5Ctext%7Bfor%20%7Dx%3D1%2Cy%3D0%5C%5C0.3%26%5Ctext%7Bfor%20%7Dx%3D0%2Cy%3D1%5C%5C0.4%26%5Ctext%7Bfor%20%7Dx%3Dy%3D1%5C%5C0%26%5Ctext%7Botherwise%7D%5Cend%7Bcases%7D)
Then
![\mathrm{Pr}[X=Y]=\mathrm{Pr}[X=Y=0]+\mathrm{Pr}[X=Y=1]=0.1+0.4=\boxed{0.5}](https://tex.z-dn.net/?f=%5Cmathrm%7BPr%7D%5BX%3DY%5D%3D%5Cmathrm%7BPr%7D%5BX%3DY%3D0%5D%2B%5Cmathrm%7BPr%7D%5BX%3DY%3D1%5D%3D0.1%2B0.4%3D%5Cboxed%7B0.5%7D)
Answer:
is y=x^2 a proportional relationship?

is y=2+x a proportional relationship?

is y=2/x a proportional relationship?

is y=2x a proportional relationship?

Answer:
48153.3
Step-by-step explanation:
π x 16 x 52 x 56 x 3
if π = 3.14, then multiply 3.14 with the other multipliers.
Answer:
fixed
Step-by-step explanation: