Answer:
Area- (4x+3)(3x-1)
Area- (12x^2 + 9x-4x-3)
Area- (12x^2 +5x-3)
Area- 12x^2 + 5x - 3
Let me know if this helps!
Answer:
i think its A
Step-by-step explanation:
D) Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)
N=0 bc you remove the parentheses, cancel the equal terms what would be 6 being cancel it would look like -24n=3n now and move the variable to the left collet like terms and then you will divide the sides. Your answer is 0
We find the area of the total square which is 8in • 8in=64in^2 . Now we find the area of the small quadrilateral which is 4in•4in=16 in^2.
Now we subtract the area of the small quadrilateral from the big quadrilateral’s area 64in^2 -16in^2 leaving us with the are of 48in^2 of the figure
