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3 years ago

Solve for X and round to the nearest tenth

Mathematics

2 answers:

makkiz [27]3 years ago

7 0

Answer:

3.4

Step-by-step explanation:

cosx = adj/hyp

cos61° = x/7

x= cos61° * 7

*degree mode

3.39

Monica [59]3 years ago

3 0

It’s 3.4 because it is trust me

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Andy is scuba diving. He starts at sea level and then descends 10 feet in 2 1/2 minutes. Represent Andy's descent in feet per mi

Sergeu [11.5K]

Answer:

4 ft/min

Step-by-step explanation:

I'm sorry no one has helped you in 40 minutes, so let me.

Theres a fun trick when it comes to saying something 'per' something;

as you can look at the word per as a fancy word for divide.

So if I have Xylophones per Megaphone then I'm basically saying:

Xylophones divided by megaphones

So in this case its 10 feet per 2 1/2 minutes and we'd understand it as 10/2.5

Lets show this

10 ft per 2 1/2 minutes = 10/2.5 ft/min = 4 ft/min

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3 years ago

Hakims car travels 600 feet in 20 seconds. Andres mortar cycle travels 300 feet in 12 seconds. Which is faster, the car or the m

sweet [91]

Answer:

Hakims car travels 600 feet in 20 seconds. Andres mortar cycle travels 300 feet in 12 seconds. Which is faster, the car or the motorcycle?

The car is faster

Find the unit rates

The car is going 30 feet in 1 second(600 divide by 20 = 30)

The motorcycle is gonig 25 feet in 1 second(300 divide by 12 = 25)

Compare the unit rates

30 > 25

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A book has a front and a back and 400 pages. The front and back cover are each 0.9mm thick measured to 1 decimal place. Each pag

oksano4ka [1.4K]

Answer:

The answer is actually 5.17 centimeters

Step-by-step explanation:

The question is asking you to calculate the minimum thickness so you have to find the lowest bounds.

The covers are 0.9 mm to 1 d.p so the minimum thickness is 0.85 because that is the lowest bound.

The pages are 0.13 mm to 2 d.p so the minimum thickness is 0.125 as that is the lowest bound.

0.85 x 2 = 1.7 and 0.125 x 400 = 50

50 + 1.7 = 51.7 which is the minimum length.

5 0

4 years ago

Pierre stands on a level ground at the point P, 5 metres from O.

Zolol [24]

I think there is data that is missing. Please attach the drawing so that to help you

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3 years ago

Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)

strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex

if $a>0$ -------> the parabola open upward (vertex is a minimum)

if $a$ -------> the parabola open downward (vertex is a maximun)

case A) $f(x)=(x-2)^{2}$

This is a vertical parabola open upward

the vertex is the point $(2,0)$

therefore

The function $f(x)=(x-2)^{2}$ does not have a vertex on the y-axis

case B) $f(x)=x(x+2)$

$f(x)=x(x+2)=x^{2}+2x$

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+1=x^{2}+2x+1$

Rewrite as perfect squares

$f(x)+1=(x+1)^{2}$

$f(x)=(x+1)^{2}-1$

the vertex is the point $(-1,-1)$

therefore

The function $f(x)=x(x+2)$ does not have a vertex on the y-axis

case C) $f(x)=(x-2)(x+2)$

$f(x)=(x-2)(x+2)=x^{2}-2^{2}$

$f(x)=x^{2}-4$

the vertex is the point $(0,-4)$

The x-coordinate of the vertex is equal to zero

therefore

The function $f(x)=(x-2)(x+2)$ has a vertex on the y-axis

case D) $f(x)=(x+1)(x-2)$

$f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2$

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)+2= x^{2} -x$

Complete the square. Remember to balance the equation by adding the same constants to each side.

$f(x)+2+0.25= x^{2} -x+0.25$

$f(x)+2.25= x^{2} -x+0.25$

Rewrite as perfect squares

$f(x)+2.25= (x-0.50)^{2}$

$f(x)=(x-0.50)^{2}-2.25$

the vertex is the point $(0.5,-2.25)$

therefore

The function $f(x)=(x+1)(x-2)$ does not have a vertex on the y-axis

the answer is

$f(x)=(x-2)(x+2)$

6 0

3 years ago

Read 2 more answers