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3 years ago

6 The floor of a tent is 7 feet by 9 feet. What is the area of the tent floor? Pls help

Mathematics

2 answers:

beks73 [17]3 years ago

7 0

Answer:

7*9

=63feet²

Step-by-step explanation:

slavikrds [6]3 years ago

7 0

63 bc area =LxW so 7x9=63

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Calcular: E = (sec245o + tg45o) ctg37o - 2cos60o

Vlada [557]

Answer:

$-2.813$

Step-by-step explanation:

Se simplifica inicialmente la fórmula en términos de las funciones trigonométricas fundamentales (Initially, the formula is simplified in terms of fundamental trigonometric functions):

$(\sec 245^{\circ} + \tan 45^{\circ} )\cdot \cot 37^{\circ} - 2\cos 60^{\circ}$

$\left(\frac{1}{\cos 245^{\circ}}+\frac{\sin 45^{\circ}}{\cos 45^{\circ}} \right)\cdot \left(\frac{\cos 37^{\circ}}{\sin 37^{\circ}} \right) - 2\cdot \cos 60^{\circ}$

$(-2.366 + 1 )\cdot (1.327) - 1$

$-2.813$

7 0

3 years ago

If discriminant (b^2 -4ac>0) how many real solutions

MaRussiya [10]

Answer:

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

Step-by-step explanation:

To Find:

If discriminant (b^2 -4ac>0) how many real solutions

Solution:

Consider a Quadratic Equation in General Form as

$ax^{2} +bx+c=0$

then,

$b^{2} -4ac$ is called as Discriminant.

So,

If Discriminant, $b^{2} -4ac >0$

Then it has Two Real Solutions.

If Discriminant, $b^{2} -4ac < 0$

Then it has Two Imaginary Solutions.

If Discriminant, $b^{2} -4ac=0$

Then it has Two Equal and Real Solutions.

4 0

3 years ago

Write 10.3 as a multiplication question have been repeated Factor

avanturin [10]

5 times 2 plus .015 times 2

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3 years ago

A BUSHEL OF APPLES WEIGHS ABOUT 42 POUNDS. THERE ARE 4 PECKS OF BUSHELS. IT TAKES 2 POUNDS OF APPLES TO MAKE ONE PIE. HOW MANY P

madam [21]

Answer:

84 pies

Step-by-step explanation:

if you multiply 42 pounds by4 pecks. You get 168 pounds. and then you divide that by 2 and you can make 84 pies

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3 years ago

15. If x=a Sin2t (I+Cos2t) and y=b Cos 2t (1-Cos2t) then find dy/dx at =22/7*4

Sav [38]

By the chain rule,

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dt}\dfrac{\mathrm dt}{\mathrm dx}\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}$