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ryzh [129]
3 years ago
11

Which is greater 17/20 or 22/25

Mathematics
1 answer:
DIA [1.3K]3 years ago
4 0
In order to find which one is greater, get them to a common denominator.

We can get them to a common denominator of 100.

This would be:

\frac{85}{100} and \frac{88}{100}

As you can see \frac{88}{100} \ \textgreater \ \frac{85}{100}.

\frac{22}{25} is greater.
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At a physics convention, 10 companies set up equal sized square booths in a row along one wall of the convention center. The boo
exis [7]
I'm not 100% sure what this all means because I'm in a different school but, I believe they have a side length of 4600.


P.S. If it doesn't work, I am so sorry
3 0
3 years ago
A farmer raises only ducks and pigs. There are 55 animals in all on his farm, and 146 legs.
nordsb [41]

Answer:

Number of ducks = 37

Number of pigs = 18

Step-by-step explanation:

Let,

x be the number of ducks

y be the number of pigs

According to given statement;

x+y=55     Eqn 1

2x+4y=146     Eqn 2 (As ducks will have 2 legs and pigs will have 4)

Multiplying Eqn 1 by 2

2(x+y=55)

2x+2y=110    Eqn 3

Subtracting Eqn 3 from Eqn 2

(2x+4y)-(2x+2y)=146-110

2x+4y-2x-2y=36

2y=36

Dividing both sides by 2

\frac{2y}{2}=\frac{36}{2}\\y=18

Putting y=18 in Eqn 1

x+18=55

x = 55-18

x = 37

Hence,

Number of ducks = 37

Number of pigs = 18

8 0
3 years ago
What is the estimate of 405?
mario62 [17]

Answer:

400


Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Q10. Assertion: 2.05 Kg = 20500 g.
jeyben [28]

Answer:

b. only reason is correct

2.05 kg=2.05 ×1000 g

=2050 g

so the Assertion is incorrect

5 0
3 years ago
What is the form of the Pythagorean triple generator?​
stepladder [879]

Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

Step-by-step explanation:

We can rewrite left side into right side form

(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)

we can expand it

(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4

(x^2+y^2)^2=x^4+y^4+2x^2y^2

we can add and subtract 2x^2y^2

(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2

(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2

(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2

4 0
3 years ago
Read 2 more answers
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