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vodka [1.7K]
3 years ago
8

kirk has 42 pieces of candy to divide evenly between his three children. if he puts the pieces into three boxes how many pieces

of candy are there per box
Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0
14 pieces of candy in the box
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(5a+4b)^{3} =(5a+4b)(5a+4b)^{2}= (5a+4b)[ (5a)^{2}+2(5a)(4b)+ (4b)^{2}]

=(5a+4b)[ 25a^{2}+40ab+ 16b^{2}]

=(5a)[ 25a^{2}+40ab+ 16b^{2}]+(4b)[ 25a^{2}+40ab+ 16b^{2}]

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Answer:

V= (5a+4b)^{3},

or 

125a^{3}+300a^{2} b+240ab^{2} + 64b^{3}


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