Answer:
Part 1) 
Part 2) 
Step-by-step explanation:
we have
![f(x)=\sqrt[3]{x} +1](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%20%2B1)
Part 1) Find f(125)
we know that
f(125) is the value of the function f(x) when the value of x is equal to 125
so
For x=125
substitute in the function
![f(125)=\sqrt[3]{125} +1](https://tex.z-dn.net/?f=f%28125%29%3D%5Csqrt%5B3%5D%7B125%7D%20%2B1)
Remember that
substitute
![f(125)=\sqrt[3]{5^{3}} +1](https://tex.z-dn.net/?f=f%28125%29%3D%5Csqrt%5B3%5D%7B5%5E%7B3%7D%7D%20%2B1)
Applying the power of rule
![\sqrt[3]{5^{3}}=(5^{3})^{\frac{1}{3}}= (5)^{3*\frac{1}{3}}=5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B5%5E%7B3%7D%7D%3D%285%5E%7B3%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%20%285%29%5E%7B3%2A%5Cfrac%7B1%7D%7B3%7D%7D%3D5)
substitute
Part 2) Find f(-64)
we know that
f(-64) is the value of the function f(x) when the value of x is equal to -64
so
For x=-64
substitute in the function
![f(-64)=\sqrt[3]{-64} +1](https://tex.z-dn.net/?f=f%28-64%29%3D%5Csqrt%5B3%5D%7B-64%7D%20%2B1)
Remember that
substitute
![f(-64)=\sqrt[3]{-4^{3}} +1](https://tex.z-dn.net/?f=f%28-64%29%3D%5Csqrt%5B3%5D%7B-4%5E%7B3%7D%7D%20%2B1)
Applying the power of rule
![\sqrt[3]{-4^{3}}=(-4^{3})^{\frac{1}{3}}= (-4)^{3*\frac{1}{3}}=-4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-4%5E%7B3%7D%7D%3D%28-4%5E%7B3%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%20%28-4%29%5E%7B3%2A%5Cfrac%7B1%7D%7B3%7D%7D%3D-4)
substitute
First, multiply the top layer. 9 times 8 is 72.
now multiply the next layer. its not 15 times 20. its 7 times 20. remember the 9 times 8? well the 8 is a part of the 15. 15-8 is 7. 7 times 20 is 140. now add 140 and the 72 from the beginning. 140+72 is = to 212. please give me THE BRAINLIEST ANSWER.
Pedro made mistake in step 3.
He supposed to plug in y = 12 into the y in the equation to solve for x
Should be:
-14x - 2(2)=24
-14x - 4 = 24
-14x = 28
x = -2
3/5 + 2/7 = 0.9 (rounded to the nearest tenth) or in fraction form it would be 6/35
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