Answer:
Equation 1: 14t + 61s = 150
Equation 2: 14t + 25s = 78
Use Elimination (x)
(-1) (14t + 25s) = (78) (-1)
-14t - 25s = -78
14t + 61s = 150
+ -14t - 25s = -78
--------------------------
36s = 72
s = 2
Salad costs $2
Then find t
14t + 61(2) = 150
14t + 122 = 150
14t = 28
t = 2
Sandwich costs $2
Answer:
2) 162°, 72°, 108°
3) 144°, 54°, 126°
Step-by-step explanation:
1) Multiply the equation by 2sin(θ) to get an equation that looks like ...
sin(θ) = <some numerical expression>
Use your knowledge of the sines of special angles to find two angles that have this sine value. (The attached table along with the relations discussed below will get you there.)
____
2, 3) You need to review the meaning of "supplement".
It is true that ...
sin(θ) = sin(θ+360°),
but it is also true that ...
sin(θ) = sin(180°-θ) . . . . the supplement of the angle
This latter relation is the one applicable to this question.
__
Similarly, it is true that ...
cos(θ) = -cos(θ+180°),
but it is also true that ...
cos(θ) = -cos(180°-θ) . . . . the supplement of the angle
As above, it is this latter relation that applies to problems 2 and 3.
Hello from MrBillDoesMath!
Answer:
Choice D, x-2
Discussion:
Observe the the highest order term in the numerator is x^4 and the highest order term in the denominator is x^3. So the highest order term in their quotient is x^4/x^3 = x. Choice D is the only possible answer as all other choices start with x^2
Regards,
MrB
450,500 because 120,000 and 330,000 and 500 thats the answer
Answer:r'=0.327 m
Step-by-step explanation:
Given

angular velocity 
mass of objects 
distance of objects from stool 
Combined moment of inertia of stool and student 
Now student pull off his hands so as to increase its speed to 3.60 rev/s


Initial moment of inertia of two masses 

After Pulling off hands so that r' is the distance of masses from stool

Conserving angular momentum







