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3 years ago

HURRY!! PLEASE!!

Mathematics

1 answer:

goldenfox [79]3 years ago

5 0

Answer:

y = 56·(1/2)^(x -1)

Step-by-step explanation:

The table shows a geometric sequence with first term 56 and common ratio 1/2. The generic term for such a sequence is ...

an = a1·r^(n-1)

Substituting the problem values, we get ...

y = 56·(1/2)^(x -1)

_____

<em>Comment on answer choices</em>

All of the answer choices are missing essential math symbols, including division bars, exponentiation symbols, parentheses. As written, the only viable choice is "none of the above."

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triangle ABC is dilated by a scale factor of four to form triangle A'B'C'. what are the coordinates of vertices A', B', and C'

netineya [11]

The question did not show the original vertices of A, B, and C.

Generally, for a triangle ABC that is dilated by a scale factor of four to form triangle A'B'C', the coordinates of vertices A', B', C' are:

For A(x, y)

The coordinate of vertex A' will be A' (4x, 4y)

For B(x, y)

The coordinate of vertex B' will be B' (4x, 4y)

For C(x, y)

The coordinate of vertec C' will be C' (4x, 4y)

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1 year ago

Whats the estimate of 73 × 64

amid [387]

Hello! Here is your answer! ☺

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3 years ago

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AREA, PERMITER AND VOLUME QUESTIONS.

castortr0y [4]

Answer:

Step-by-step explanation:

(A) The radius of the circle is=1.8m

Then diameter will be: 2r= $2{\times}1.8=3.6 m$

Circumference of circle= ${\pi}d$ = $3.14{\times}3.6=11.304 m$

Area of the circle= ${\pi}r^{2}=3.14{\times}(1.8)^{2}=10.17 m^{2}$

(B) The area of the rectangular backboard of basketball court = 18900 $cm^{2}$

Width=180cm

Area of rectangle= l{\times}b[/tex]

18900=l{\times}180[/tex]

$l=105 cm=1.05m$

Perimeter of the seating space=2(l+b)

= $2(32.5+18.4)$

= $101.8 m$

Perimeter of the basketball court=2(l+b)

= $2(15+28)$

= $86 m$

Now, total perimeter= perimeter of the basketball court+perimeter of the seating space.

Total perimeter= $101.8+86=187.8 m$

Area of the seating space= $l{\times}b$

= $32.5{\times}18.4=598 m^{2}$

Area of 4 triangles= $4{\times}(\frac{1}{2}{\times}B{\times}H)$

= $4{\times}(\frac{1}{2}{\times}3{\times}2)=12m^{2}$

Area of the shape= Area of the square+ area of the 4 triangles

= $9+12=21m^{2}$

(D) Perimeter of rectangle with length=40 m (After converting cm to m) and breadth= 10 m is given by: $2(l+b)=2(40+10)=100 m$

Perimeter of rectangle with length 68 m and breadth=33 m is given by: $2(l+b)=2(68+33)=202 m$

Perimeter of the semicircle= $\frac{{\pi}d}{2}=\frac{3.14{\times}34}{2}=53.38 m$

Total perimeter= $100+201+53.38=355.38 m$

Area of rectangle with length=40 m (After converting cm to m) and breadth= 10 m is given by: $l{\times}b=40{\times}10=400 m^{2}$

Area of rectangle with length 68 m and breadth=33 m is given by: $l{\times}b=68{\times}33=2244 m^{2}$

Area of the semi circle= $\frac{{\pi}r^{2}}{2}=\frac{3.14{\times}17^{2}}{2}=453.73 m^{2}$

Total area= $400+2244+453.73=3097.73 m^{2}$

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3 years ago

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Q #8 please solve my question

stealth61 [152]

The 2nd one. The one that says CD=DA, DA=ZX, AC=YZ

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4 years ago

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What is the product of all non- zero integers between -6 and 4

deff fn [24]

The product is -720.

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-5, -4, -3, -2, -1, 1, 2, 3

and the product of all these numbers would be -720.

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