3 years ago

Im in pain lololololollololololol please help

Mathematics

1 answer:

AURORKA [14]3 years ago

5 0

Answer:

20.2

Step-by-step explanation:

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How do i do these inverse trig

jok3333 [9.3K]

This is a right triangle
so
Cos x = 109 / 134 then x = cos⁻¹ (109/134) = 35.567°
sin y = 109 / 134 then y = sin⁻¹ (109/134) = 54.433°
and
the third side = √(134² - 109²) = 77.94

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3 years ago

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Please help me grades are do today

11111nata11111 [884]

Answer:

Step-by-step explanation:

$sin=\frac{opp}{hyp}$

$cos = \frac{adj}{hyp}$

$cos^{-1}\left(\frac{45}{51}\right)$

which is 28.07 degree

$sin\left(28.07\right)=\frac{x}{51}$

x= 23.99

23.99+4=h=28

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2 years ago

Can you help I'm confused

Brrunno [24]

Answer:

x ≤ 5

Step-by-step explanation:

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3 years ago

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A right triangle has a hypotenuse length of 12, and one side length of 9. find the missing side length. do the side lengths form

Rina8888 [55]

Use the Pythagorean theorem:

$a^2+b^2=c^2$

c - a hypotenuse

a, b - legs

We have: a = 9 and c = 12. Substitute:

$9^2+b^2=12^2$

$81+b^2=144$ <em>subtract 81 from both sides</em>

$b^2=63\to b=\sqrt{63}\\\\b=\sqrt{9\cdot7}\\\\b=\sqrt9\cdot\sqrt7\\\\ \boxed{b=3\sqrt{7}}$

A Pythagorean triple consists of three positive integers a, b and c, such that

$a^2+b^2=c^2$ .

$b=3\sqrt{7}$ is not positive integer.

<h3>The sides of the triangle do not form a pythagorean triple.</h3>

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3 years ago

F= z-g/n<br> solve for z

Vera_Pavlovna [14]

Z= F+ (g/n) (you’re welcome)

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3 years ago