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Maksim231197 [3]
3 years ago
14

Pleaseeeee help with 7-12 I’m strugglingggg!!!

Mathematics
2 answers:
Troyanec [42]3 years ago
7 0
7) go right 5 then up 3 and make a dot at that point and then go right 10 then go up 8 then make a dot at that point an then connect the dots

8) go left 5 then go up 14 and make a dot and then go left 1 and up 2 then make a dot and connect the dots

9) go left 5 and up 6 then make a dot at that point and then go right 8 and up 6 and make a dot and then connect the dots

10) go left 4 and down 17 then make a dot then go left 4 and down 3 and make a dot and then connect the dots

11) go right 12 and down 7 and make a dot then go right 2 and down 2 and make a dot then connect the dots

12) go left 3 then down 10 and make a dot then go left 1 and down 1 and make a dot then connect the dots.

So basically just graph the points the connect them for each each problem
bearhunter [10]3 years ago
5 0

Answer:

7-12 is 5

Step-by-step explanation:

First you want to turn this into addition and make 12 it's inverse 7+(-12) now with 7+(-12) it is basically 12-7. 12-7=5 so your answer is 5

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PLEASE HELP!!!!<br><br>Which of the following functions is graphed below?!?
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<u>The answer is option c.</u>

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Find the distance between the points (-3, 11) and (5, 5).<br><br> 10<br> 2<br> 2
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Use the distance formula to find the distance between two points.

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Water is pumped into a tank at a rate of r (t)=30(1−e− 0.16t) gallons per minute, where t is the number of minutes since the pum
Vlad1618 [11]

Answer:

The total volume of the water in the tank after 20 minutes = 1220 gallons

Step-by-step explanation:

Rate of water pumped into the tank  r (t) = 30 (1 - e^{-0.16 t} )

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The water in the tank after 20 minutes = Initial volume of water in the tank + Volume of water being pumped in the tank

V_{total} = V_{i} + V_{pump}

V_{pump} = \int\limits^a_b {r(t)} \, dt

Where a = 0 , b = 20

Put the value of r (t) in above equation we get

V_{pump} = \int\limits^a_b {30 (1 - e^{-0.16t} )} \, dt

V_{pump} = 30 [ t + \frac{e^{-0.16t} }{0.16} ]

V_{pump} = 30[ (20- 0) + \frac{1}{0.16}(e^{-0.16 (20)}- e^{0}  )

V_{pump} = 420 gallon

Now, total volume in the tank

V_{total} = V_{i} + V_{pump}

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Therefore the total volume of the water in the tank after 20 minutes = 1220 gallons

3 0
3 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

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Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

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