PLEASE HELP, is this graph parallel, perpendicular or neither?

Mathematics

1 answer:

Pie3 years ago

8 0

Answer:

Step-by-step exp perpendicular becaus it makes a 90 degree angle

You might be interested in

Describe how to transform the graph of f into the graph of g.

Leokris [45]

We are given with two functions f(x)= x^2 and g(x) = -x^2. in this case, we can plot the first equation having a y with two values -x and x. On the other hand, in the second function, when we use the same values of x, the y-value is the negative of the y-value in used in the first equation. Hence the answer is 4)reflect the graph of f across the x axis.

5 0

3 years ago

I need help with these questions for Working with Standard and Vertex Forms of the Quadratic Function, the first image is the in

Arlecino [84]

9514 1404 393

Answer:

3 (7e) f(x) = -3(x +2)^2 +1; D: (-∞, ∞); R: (-∞, 1]

4 (8) g(x) = 4(x -3)^2 -5; x = 3; (3, -5); min: -5; D: (-∞, ∞); R: [-5, ∞)

5 (10) A(175) = 31,250 m^2

Step-by-step explanation:

Q3. (7e) f(x) = -3x^2 -12x -11 = -3(x^2 +4x) -11 = -3(x^2 +4x +4) -11 +3(4)

f(x) = -3(x +2)^2 +1

Domain: all real numbers; Range: y ≤ 1

Expanded: -3(x^2 +4x +4) +1 = -3x^2 -12x -11

Q4. (8a) g(x) = 4(x^2 -6x) +31 = 4(x^2 -6x +9) +31 -4(9)

g(x) = 4(x -3)^2 -5

8b) x = 3 . . . axis of symmetry

8c) (3, -5) . . . coordinates of vertex

8d) minimum: -5 (parabola opens upward from vertex, which is the minimum)

8e) any quadratic has a domain of "all real numbers"

8f) the range is upward from the minimum: y ≥ -5

8g) see attached

Q5. (10) A(x) = 700x -2x^2 = -2(x^2 -350x +30625) +2(30625)

A(x) = -2(x -175)^2 +31,250

The maximum area that can be enclosed is 31,250 square meters.

_____

Additional comment

The process of "completing the square" can be done using the following steps. (a) Factor out the leading coefficient from the variable terms; (b) determine the linear term coefficient inside parentheses, and add the square of half of it inside parentheses; (c) add the opposite of the same quantity outside parentheses (make sure the leading coefficient is properly factored in; (d) rewrite the parentheses as a square, and collect terms outside parentheses. In the final form a(x -h)^2 +k, the vertex is (h, k).