x-2 is a factor so x = 2 is a root of f(x)
This is because f(x) = (x-2)*g(x) for some polynomial g(x). We don't have to worry about what g(x) is equal to as it doesn't affect the status of the root we're after.
So,
f(x) = 0
(x-2)*g(x) = 0
x-2 = 0 or g(x) = 0
x = 2 or g(x) = 0
This shows how the factor x-2 leads to the root x = 2
Therefore, f(2) = 0
Answer: Choice D
Hello there.
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Write two others names for fg
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Answer: FD, GF
Answer:
½pi or 0.5pi units²
Step-by-step explanation:
Area : angle
9pi : 2pi
x : pi/9
9pi/2pi = x/(pi/9)
4.5 × pi/9 = x
x = ½pi or 0.5pi units²
Answer:
Domain = (
-∞,∞), {x|x ∈ R}
Range (-∞,2], {y|y ≤ 2}
Vertex (h,k) = (6,2)
Step-by-step explanation:
(Domain / Range) The absolute value expression has a V shape. The range of a negative absolute value expression starts at its vertex and extends to negative infinity.
(Vertex) To find the x coordinate of the vertex, set the inside of the absolute value
x − 6 equal to 0 . In this case, x − 6 = 0 .
x−6=0
Add 6 to both sides of the equation.
x=6
Replace the variable x with 6 in the expression.
y=−1/3⋅|(6)−6|+2
Simplify−1/3⋅|(6)−6|+2.
y=2
The absolute value vertex is ( 6 , 2 ) .
(6,2)
Hope this helps