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allsm [11]
2 years ago
9

Help me Guess just help please

Mathematics
2 answers:
MAXImum [283]2 years ago
5 0
45 Is the right answer because it is
wolverine [178]2 years ago
4 0

Answer:

45

Step-by-step explanation:

yes yes i think this is very correct very yes

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Year 2 revenue is 5,000,000 at 32%By what percent would you need to
azamat
x= \frac{3,000,000}{5,000,000} \cdot100\%-32\%= \frac{3}{5}\cdot100\%-32\%=60\%-32\%=28\%\\\\Ans.\ You\ need\ increase\ 28\%
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3 years ago
Please answer this question !! BRAINLIEST !!
Misha Larkins [42]

Cos inverse0.7813

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3 years ago
How to determine if the columns of a matrix are linearly independent?
astra-53 [7]
Let's consider an arbitrary 2x2 matrix as an example,

\mathbf A=\begin{bmatrix}\mathbf x&\mathbf y\end{bmatrix}=\begin{bmatrix}x_1&y_1\\x_2&y_2\end{bmatrix}

The columns of \mathbf A are linearly independent if and only if the column vectors \mathbf x,\mathbf y are linearly independent.

This is the case if the only way we can make a linear combination of \mathbf x,\mathbf y reduce to the zero vector is to multiply the vectors by 0; that is,

c_1\mathbf x+c_2\mathbf y=\mathbf 0

only by letting c_1=c_2=0.

A more concrete example: suppose

\mathbf A=\begin{bmatrix}1&2\\4&8\end{bmatrix}

Here, \mathbf x=\begin{bmatrix}1\\4\end{bmatrix} and \amthbf y=\begin{bmatrix}2\\8\end{bmatrix}. Notice that we can get the zero vector by taking c_1=-2 and c_2=1:

-2\begin{bmatrix}1\\4\end{bmatrix}+\begin{bmatrix}2\\8\end{bmatrix}=\begin{bmatrix}-2+2\\-8+8\end{bmatrix}=\mathbf 0

so the columns of \mathbf A are not linearly independent, or linearly dependent.
8 0
3 years ago
A student got a juice box for $2.50 and some bags of chips for $0.85 each bag. The total cost was $5.05. What equation can be us
lozanna [386]

Answer:

He got scammed for paying $2.50 for a Juice box

3 0
3 years ago
Read 2 more answers
5!.4! is equivalent to:<br> O (5)(41)?<br> O (5)(41)?<br> O 20!
Xelga [282]
The answer would be a (5) (41) hope that helped
5 0
2 years ago
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