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34kurt
4 years ago
13

Find the lcm of 6, 5, 3

Mathematics
2 answers:
umka2103 [35]4 years ago
7 0
Hello There!

6 = 6 12 18 24 30 36
5 = 5 10 15 20 25 30
3 = 3 6 9 12 15 18 21 24 27 30

It would be 30.

Hope This Helps You!
Good Luck :)
snow_lady [41]4 years ago
5 0
The LCM's of 6, 5, and 3. To solve this question, let's list the multiples.

6: 6, 12, 18, 24, 30
5: 5, 10, 15, 20, 25, 30
3: 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

As you can see, all of the three numbers have a multiple of 30. The LCM of 6, 5, and 3 is 30.
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OLEGan [10]

Answer:

Use Desmos Graphing Calculator if you have more problems like this

8 0
3 years ago
For football tryouts, 12 coaches and 42 players will split into groups. Each group will have the same numbers of coaches and pla
Ymorist [56]

gratest common factor for 12 and 42 is 6

 so 6 groups can be formed

12/6 = 2

42/6 = 7

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4 0
4 years ago
Which of the following describes a compound event? A. getting a 5 on a spin B. getting tails on a coin toss C. drawing an ace fr
Sphinxa [80]
A. getting a 5 on a spin : NO, I's a simple event
B. getting tails on a coin toss : NO, I's a simple event
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4 0
4 years ago
Read 2 more answers
QUESTION 2
Mekhanik [1.2K]

Answer:

3/30 =1/10

Step-by-step explanation:

add up the number of balls and then

number of black balls divided by the total number of balls.

5 0
4 years ago
The 3rd term of (a-b)4 is
fgiga [73]

The third term of the expansion is 6a^2b^2

<h3>How to determine the third term of the expansion?</h3>

The binomial term is given as

(a - b)^4

The r-th term of the expansion is calculated using

r-th term = C(n, r - 1) * x^(n - r + 1) * y^(r - 1)

So, we have

3rd term = C(4, 3 - 1) * (a)^(4 - 3 + 1) * (-b)^(3-1)

Evaluate the sum and the difference

3rd term = C(4, 2) * (a)^2 * (-b)^2

Evaluate the exponents

3rd term = C(4, 2) * a^2b^2

Evaluate the combination expression

3rd term = 6 * a^2b^2

Evaluate the product

3rd term = 6a^2b^2

Hence, the third term of the expansion is 6a^2b^2

Read more about binomial expansion at

brainly.com/question/13602562

#SPJ1

4 0
1 year ago
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