Question

Find the solution set for this equation: -a2+4a=0 (Separate the two values with a comma)

Answer 1

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: \{ 0,4 \}$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: - {a}^{2} + 4a = 0$

$\qquad \tt \rightarrow \: - ( {a}^{2} - 4a) = 0$

$\qquad \tt \rightarrow \: {a}^{2} - 4a = 0$

$\qquad \tt \rightarrow \:a(a - 4) = 0$

The two cases are :

• a = 0

or

• a -4 = 0, that leads to a = 4

We can conclude :

$\qquad \tt \rightarrow \:solution \: (a) = \{ 0,4\}$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer 2

$\quad \quad \quad \quad\huge \tt \pink ❆ AnSweR \pink ❆$

$\quad\quad \tt-a^2+4a= 0$

$\: \: \: \: \: \: \: \: \: \: \:$

$\quad\quad\tt⇢-1(a^2 - 4a) = 0$

$\: \: \: \: \: \: \: \: \: \: \:$

$\quad\quad\tt⇢-1(a-4)a = 0$

$\: \: \: \: \: \: \: \: \: \: \:$

$\quad\quad\tt⇢a-4=0$

$\: \: \: \: \: \: \: \: \: \: \:$

$\quad\quad\tt⇢a = 0$

-----------------------------------------------------------

$\boxed{ \tt \blue{a = 0}}$

$\boxed{ \tt\blue{a = 4}}$