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2 years ago

Does anyone understand this? i need help

Mathematics

2 answers:

Pachacha [2.7K]2 years ago

7 0

Answer:

i know it is the 2 one i am sure

Step-by-step explanation:

Gnesinka [82]2 years ago

6 0

Answer:

$81^{1/4}$

Step-by-step explanation:

$\sqrt[4]{81} = 81^{1/4}$

a square root can be equivalently written as a fractional exponent. All the other options can be ruled out as they are simply incorrect.

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Margie wants to collect 3600 cans of food to donate to the community food bank.She plans to collect equal number of can for 4 mo

Alex777 [14]

Answer:

If its per month then its 900

Step-by-step explanation:

3600/4 = 900

900*4 = 3600

5 0

2 years ago

the first four terms of a geometric progression are 2,10,50,250 a) write down the common ratio of the progression b) write down

VLD [36.1K]

Answer:

The common ratio is 5 and the 5th term is 1250

Step-by-step explanation:

The common ratio is given by

r=U(2)/U (1)

=10/2

The fifth term

U (n)=ar^n-1

U(5)=2(5)^5-1

=2×5^4

=2×625

=1250

3 0

3 years ago

What are the first three terms of the sequence...plz help pt.1

svetlana [45]

$a_{n} \: = \: 2(a_{n - 1})^{2} \\ a_{1} = 4 \: (given) \\ a_{2} = \: 2(a_{2 - 1})^{2} \\ = 2(a_{ 1})^{2} \\ = 2 \times {4}^{2} \\ = 32 \\ \\ a_{3} = \: 2(a_{3 - 1})^{2} \\ = 2(a_{ 2})^{2} \\ = 2 \times {32}^{2} \\ = 2 \times 1024 \\ = 2048$

so first 3 terms are

4, 32, 2048

8 0

3 years ago

Read 2 more answers

What is the measurement of angle B

Liono4ka [1.6K]

Angles B and D are congruent so:

(360-112-74)/2=87°

6 0

3 years ago

Read 2 more answers

Graph this rational equation. Identify the points of discontinuity, holes, vertical asymptotes, x-intercepts, and horizontal asy

irakobra [83]

Step-by-step explanation:

We have given,

A rational function : f(x) = $\frac{x-2}{x-4}$

W need to find :

Point of discontinuity : - At x = 4, f(x) tends to reach infinity, So we get discontinuity point at x =4.

For no values of x, we get indetermined form (i.e $\frac{0}{0}$ ), Hence there is no holes

Vertical Asymptotes:

Plug y=f(x) = ∞ in f(x) to get vertical asymptote {We can us writing ∞ = $\frac{1}{0}$ }

i.e ∞ = $\frac{x-2}{x-4}$

or $\frac{1}{0}=\frac{x-2}{x-4}$

or x-4 =0

or x=4, Hence at x = 4, f(x) has a vertical asymptote

X -intercept :

Plug f(x)=0 , to get x intercept.

i.e 0 = $\frac{x-2}{x-4}$

or x - 2 =0

or x = 2

Hence at x=2, f(x) has an x intercept

Horizontal asymptote:

Plug x = ∞ in f(x) to get horizontal asymptote.

i.e f(x) = $\frac{x-2}{x-4}$ = $\frac{x(1-\frac{2}{x} )}{x(1-\frac{4}{x} )}$

or f(x) = $\frac{(1-\frac{2}{∞} )}{(1-\frac{4}{∞} )}$

or f(x) = 1 = y

hence at y =f(x) = 1, we get horizontal asymptote

4 0

3 years ago