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Anton [14]
3 years ago
5

If the outlier is removed, which measure will not change? mean median mode range

Mathematics
1 answer:
Elena-2011 [213]3 years ago
5 0

Answer:

Out of mean, median, mode, and range, the answer to this question is mode. If an outlier is removed, mode will not change. Hope this helps!

You might be interested in
Express the following as standard numbers:
Ksenya-84 [330]

Answer:

A. 56,000

B. 784,000,000

C. 620

D. 0.00000432

Step-by-step explanation:

{ \tt{}}

5 0
3 years ago
1/7 x X =1 <br> X x 1/11=1<br> 1 divided by 1/5=
guajiro [1.7K]

Answer:

  1. x = 7
  2. x = 11
  3. 5

Step-by-step explanation:

\frac{1}{7}  \times x = 1

7 \times  \frac{1}{7} x = 7 \times 1

7 \times  \frac{1}{7} x = 7

\boxed{\green{x = 7}}

◇◇•◇◇

x \times  \frac{1}{11}  = 1

\frac{1}{11} x  = 1

11 \times  \frac{1}{11} x = 11 \times 1

11 \times  \frac{1}{11} x = 11

\boxed{\green{x = 11}}

♤♤•♤♤

1 \div  \frac{1}{5}  = 1 \times  \frac{5}{1}

1 \times 5

\boxed{\green{= 5}}

4 0
3 years ago
what is te discontinuity of the function f(x) = the quantity of x squared plus 6x plus 8 all over x plus 4?
seropon [69]

Answer:

A hole at x=-4.

Step-by-step explanation:

This is a fraction so we have to worry about division by zero.

The only time we will be dividing by 0 is when x+4 is 0.

Solving the equation

x+4=0 for x:

Subtract 4 on both sides:

x=-4

So there is either a vertical asymptote or a hole at x=-4.

These are the kinds of discontinuities we can have for a rational function.

If there is a hole at x=-4, then x=-4 will make the top zero and can be cancelled out after simplification.

If is is a vertical asymptote, x=-4 will make the top NOT zero.

Let's see what -4 for x in x^2+6x+8 gives us:

(-4)^2+6(-4)+8

16+-24+8

-8+8

0

Top and bottom are 0 when x=-4.

Let's see what happens after simplication.

We are going to factor a^2+bx+c if factorable by finding two numbers that multiply to be c and add up to be b.

So what 2 numbers together multiply to be 8 and add up to be 6.

I hoped you said 4 and 2 because (4)(2)=8 where 4+2=6.

\frac{x^2+6x+8}{x+4}=\frac{(x+4)(x+2)}{x+4}=x+2

We we able to cancel out that factor that was giving us x=-4 is a zero.  

Therefore there is a hole at x=-4.

7 0
3 years ago
Find the value of x and the measure of the angle labeled 3x.
nalin [4]

Answer:

X=10

Step-by-step explanation:

3x=30

3(10)=30

30=30

30+42=72

I hope this helps!

8 0
3 years ago
Read 2 more answers
What is the product of the two binomial below
Svetach [21]
This is a difference of squares, meaning that when you multiply the binomials it would be the front term squared minus the last term squared.

The front term squared = (3A) squared = 9A squared
The last term squared = (4B) squared = 16B squared

Final Answer: D. 9A squared - 16B squared
4 0
3 years ago
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