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zhuklara [117]
3 years ago
7

Can some arguments have more than one conclusion

SAT
1 answer:
topjm [15]3 years ago
6 0

Explanation:

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The function h(t)= -16t^2 +32t +6 can be used to model the height of a ball, in feet, t seconds after it is thrown into the air.
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I AM TOTAALLY BORED WITH SCHOOL
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Identify which strategy is likely to result in the greatest increase in the San Joaquin kit fox population. Explain why the stra
STALIN [3.7K]

The strategy that is likely to result in the greatest increase in the San Joaquin kit fox population is strategy one.

<h3>Which change is said to be responsible for the decline of the kit fox population A?</h3>

Habitat destruction and fragmentation is known to be the factor that has led to  and has been identified as the most vital cause of the kit fox's decline and it is one that has threatens the species' consistent viability.

So, the  human intervention that would most likely protect and keep the kit fox populations is through the  Introduction of  a species that can be able to act as the new kit fox food source.

Hence, The strategy that is likely to result in the greatest increase in the San Joaquin kit fox population is strategy one.

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2 years ago
Identify the reference angle es001-1. Jpg for each given angle, es001-2. Jpg. Es001-3. Jpg degrees. Es002-1. Jpg degrees. Es003-
julia-pushkina [17]

The reference angle is the smallest angle between the terminal side and the x-axis.

(1)\ \theta = 300^o

300 degrees is in the 4th quadrant.

So, the reference angle is

\alpha = 360 - \theta

\alpha = 360 - 300

\alpha = 60^o

Hence, the reference angle of 300 degrees is 60 degrees

(2)\ \theta = 225^o

225 degrees is in the 3rd quadrant.

So, the reference angle is

\alpha = \theta - 180

\alpha = 225 - 180

\alpha = 45^o

Hence, the reference angle of 225 degrees is 45 degrees

(3)\ \theta = 480^o

480 degrees is in the 2nd quadrant (i.e. 480 - 360 = 120)

So, the reference angle is

\alpha = 180 - \theta

\alpha = 180 - 120

\alpha = 60^o

Hence, the reference angle of 480 degrees is 60 degrees

(2)\ \theta = -210^o

-210 degrees is in the 2nd quadrant (i.e. 360 - 210 = 150)

So, the reference angle is

\alpha = 180 - \theta

\alpha = 180 - 150

\alpha = 30^o

Hence, the reference angle of -210 degrees is 30 degrees

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When the Chick-fil-A is sus…
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Agreed, just a liiiiiittle too sus but hey, we all have our own levels XD

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