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kipiarov [429]
3 years ago
9

What is the fully simplified answer to sqrt(7/18) + sqrt(5/8) - sqrt(7/2)

Mathematics
1 answer:
NeX [460]3 years ago
6 0

Answer:

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

Step-by-step explanation:

Given expression as:

=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }

We need to simplify the given expression.

Solution:

We have:

=\sqrt{\frac{7}{18}}+\sqrt{\frac{5}{8}}-\sqrt{\frac{7}{2} }

Rewrite the expression as:

=\frac{\sqrt{7}}{3\sqrt{2}} - \frac{\sqrt{7}}{\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}

\frac{\sqrt{7}}{\sqrt{2} } is a common factor to the first two terms.

Using distributive property we can factor out \frac{\sqrt{7}}{\sqrt{2} } from the first two terms.

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1}{3} -1)  +\frac{\sqrt{5}}{2\sqrt{2}}

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{1-3}{3})  +\frac{\sqrt{5}}{2\sqrt{2}}

=\frac{\sqrt{7}}{\sqrt{2}}(\frac{-2}{3})  +\frac{\sqrt{5}}{2\sqrt{2}}

=-\frac{2\sqrt{7}}{3\sqrt{2}} +\frac{\sqrt{5}}{2\sqrt{2}}

\sqrt{2} is common factor, so we can factor \sqrt{2} from the above expression.

=\frac{1}{\sqrt{2} }( -\frac{2\sqrt{7}}{3} +\frac{\sqrt{5}}{2})

=\frac{1}{\sqrt{2} }( \frac{-2\times 2\sqrt{7}+3\times \sqrt{5}}{6})

=\frac{1}{\sqrt{2} }( \frac{-4\sqrt{7}+3\sqrt{5}}{6})

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

Therefore, we get simplified answer as.

=\frac{-4\sqrt{7}+3\sqrt{5}}{6\sqrt{2}}

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Hello!

First you have to list the data in both classes

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41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90

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First we are going to find the mode and mean of class A

The mode is the number that appears the most

The number that appears the most is 61

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We are going to find the range and median for class B

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To find the median you list the numbers from least to greatest and look for the number in the middle

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The number in the middle is 78

The range is 54 and the median is 78
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Hope this helps!
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