Answer:
You must survey 784 air passengers.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
The margin of error is:
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
Assume that nothing is known about the percentage of passengers who prefer aisle seats.
This means that 
, which is when the largest sample size will be needed.
Within 3.5 percentage points of the true population percentage.
We have to find n for which M = 0.035. So
You must survey 784 air passengers.
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Answer:
Step-by-step explanation:
a. 5/2 ÷ 1/2 =
b. 6/9 ÷ 5/6
c. 3/6 ÷ 2/5
d. 7 1/2 ÷ 6
=
e. 1 1/3 ÷ 1 2/3=
- 4/3 ÷ 5/3 =
- 4/3 * 3/5 =
- 4/5
15) factor out cos: cos(x)(sin(x)+1)=0
Now this is true when either cos(x)=0 (x=pi/2 and 3pi/2)
Or when sin(x)=-1 (x=3pi/2)
So it's solutions are pi/2 and 3pi/2
