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marshall27 [118]
1 year ago
13

Jay is hanging 160 feet of Christmas garland on the three sides (two on the width and one on the length) of fencing that enclose

his rectangular front yard. The length is eight feet less than four times the width. Find the length and width of the fencing.
Mathematics
1 answer:
Setler [38]1 year ago
3 0

The length of the fencing is 62.4 feet.

The width of the fencing is 17.6 feet.

Given,

The measurement of the Christmas garland = 160 feet

The width of the fencing = w

The length of the fencing, l = 4w - 8

We have to find the length and width of the fencing.

Here,

Perimeter can be taken as 160. Because garland will cover the entire fencing.

Perimeter = 2(l + w)

160 = 2(4w - 8 + w)

160 = 2(5w - 8)

160/2 = 5w - 8

80 + 8 = 5w

88/5 = w

width = 17.6 feet

Now,

l = 4w - 8

l = 4 × 17.6 - 8

l = 70.4 - 8

length = 62.4 feet

That is,

The length of the fencing is 62.4 feet.

The width of the fencing is 17.6 feet.

Learn more about perimeter here:

brainly.com/question/13023749

#SPJ1

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