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Tcecarenko [31]
4 years ago
7

What is the midpoint of a segment whose in endpoints are 5,8 and 11,6

Mathematics
1 answer:
slamgirl [31]4 years ago
3 0

Answer:

8,7

Step-by-step explanation:

Add both "x" coordinates, divide by 2.

Add both "y" coordinates, divide by 2.

so x1+x2/2 and y1+y2/2

so 5,8 and 11,6 5+11=16 and then 16/2=8

then take your cords from y axis so 8+6=14 and then 14/2=7

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PLSSS HELP IF YOU TURLY KNOW THISS
xxMikexx [17]

Answer:

2 1/2

Step-by-step explanation:

Turn both fractions into improper fractions, multiply the whole number by the denominator and add the numerator.

4 3/4

4 * 4 + 3 = 19

19/4

2 1/4

2 * 4 + 1 = 9

9/4

Now since she drank 2 1/4 gallons of juice, subtract 9/4 from 19/4.

19/4 - 9/4 = 10/4

Now turn back into a mixed fraction, do this by putting 4 into ten twice and taking the remainder and putting it as numerator:

4 * 2 = 8

10 - 8 = 2

2 1/2

8 0
3 years ago
Solve the system of equations 7x+10y=36 y=2x+9
Damm [24]

Answer:

x = -2

y = 5

Step-by-step explanation:

Given two equations

1. 7x + 10y = 36

2. y = 2x + 9

Substitute 2x + 9 for y in equation 1.

We have

7x + 10y = 36

7x + 10(2x + 9) = 36

Distribute 10 into (2x + 9)

We have

7x + 10 x 2x + 10 x 9 = 36

7x + 20x + 90 = 36

27x + 90 = 36

Subtract 90 from both sides to eliminate 90 on the left side

27x + 90 - 90 = 36 - 90

27x = -54

Divide both sides by 27 to isolate x

27x/27 = -54/27

x = -2

Now substitute -2 into either equation to get y

Using equation 2, we have

y = 2x + 9

= 2 x -2 + 9

= -4 + 9

= 5

x = -2

y = 5

Check

7(-2) + 10(5) = 36

5 0
3 years ago
The earth travels 584 million miles in one year it takes to go around the sun. If there are 365 days in one year what speed does
EleoNora [17]

Answer:

1000miles per hour

Step-by-step explanation:

4 0
3 years ago
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pav-90 [236]
THE SECOND ONE IS THE CORRECT ANSWER (B)

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5 0
4 years ago
Read 2 more answers
What are the points for f(x)=3^(x-1)-2
Savatey [412]

Answer:  (0, -1 \frac{2}{3}), (1, -1), (2, 1)

<u>Step-by-step explanation:</u>

Set the exponent equal to zero - <em>that is your anchor point</em>.

Then choose an x-value less than and greater than the anchor point.

\left\begin{array}{c|c|l}&\underline{\quad x\quad }&\underline{\qquad \qquad f(x)\qquad \qquad \qquad \quad }\\\text{less than anchor}&0&3^{0-1}-2=3^{-1}-2=\frac{1}{3}-2 = -1\frac{2}{3}}\\\\anchor\ point&1&3^{1-1}-2=3^{0}-2=1-2 = -1}\\\\\text{greater than anchor}&2&3^{2-1}-2=3^{1}-2=3-2 = 1}\end{array}\right

4 0
4 years ago
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