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IrinaVladis [17]

2 years ago

13

INEED YOUR HELP ASAP!!! For the expression 6 − y + 3, determine the coefficient for the variable term.

1 answer:

Alja [10]2 years ago

5 0

Answer:

$-1$

Step-by-step explanation:

$6 - y + 3$

$-y+3+6$

$-y+9$

A coefficient is a number that is used to multiply with a variable.

$-y=-1y$

$-1y+9$

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(I have a deadline in 3 hours :c ) Ann's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs

max2010maxim [7]

A=3B
4.35A+5.40B=780.95
Substitute 3B into A for the second equation:
4.35(3B)+5.40B=780.90
13.05B+5.40B=780.90
18.45B=780.90
B=42.33
Plug into equation 1:
A=3B
A=3(42.33)
A=126.98

7 0

3 years ago

Read 2 more answers

10Hello, can you help me with this? How much is 5 raised to 5?

vesna_86 [32]

Answer:

A 5 by 5 Power in Trust is a clause that lets the beneficiary make withdrawals from the trust on a yearly basis. The beneficiary can cash out $5,000 or 5% of the trust's so-called fair market ...

Step-by-step explanation:

5^5

=5*5*5*5*5

=5^5

=3125

6 0

2 years ago

3 part question. If answer all(brainilest will be given.

docker41 [41]

Answer:

1. 1080

2. It shows the initial debt, i.e., $1080

3.24 months

8 0

3 years ago

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

Michael took in 91 mile bike trip. he left home at 7 AM. If he stopped for a total of two hours for rest and food and averaged 1

Korvikt [17]

Distance = rate * time
t = d / r

t = 91 / 14 = 6.5 hrs

plus 2 hour rest stop

8.5 hrs

start at 7 AM
end at 3:30 PM

5 0

2 years ago