1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrews [41]
3 years ago
11

Which data set does the line plot represent? *

Mathematics
1 answer:
Komok [63]3 years ago
8 0
C ) 0, 2, 3, 3, 3, 4, 6, 9, 9, 10, 10, 10
You might be interested in
Factor polynomial below
Drupady [299]
Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
8 0
2 years ago
There are 156 laptops and desktop computers in a lab. There are 8 more laptops than desktop computers. What is the total number
timama [110]
There are 86 laptops
7 0
2 years ago
Read 2 more answers
The number of people arriving at a ballpark is random, with a Poisson distributed arrival. If the mean number of arrivals is 10,
Stella [2.4K]

Answer:

a) 3.47% probability that there will be exactly 15 arrivals.

b) 58.31% probability that there are no more than 10 arrivals.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

If the mean number of arrivals is 10

This means that \mu = 10

(a) that there will be exactly 15 arrivals?

This is P(X = 15). So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 15) = \frac{e^{-10}*(10)^{15}}{(15)!} = 0.0347

3.47% probability that there will be exactly 15 arrivals.

(b) no more than 10 arrivals?

This is P(X \leq 10)

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-10}*(10)^{0}}{(0)!} = 0.000045

P(X = 1) = \frac{e^{-10}*(10)^{1}}{(1)!} = 0.00045

P(X = 2) = \frac{e^{-10}*(10)^{2}}{(2)!} = 0.0023

P(X = 3) = \frac{e^{-10}*(10)^{3}}{(3)!} = 0.0076

P(X = 4) = \frac{e^{-10}*(10)^{4}}{(4)!} = 0.0189

P(X = 5) = \frac{e^{-10}*(10)^{5}}{(5)!} = 0.0378

P(X = 6) = \frac{e^{-10}*(10)^{6}}{(6)!} = 0.0631

P(X = 7) = \frac{e^{-10}*(10)^{7}}{(7)!} = 0.0901

P(X = 8) = \frac{e^{-10}*(10)^{8}}{(8)!} = 0.1126

P(X = 9) = \frac{e^{-10}*(10)^{9}}{(9)!} = 0.1251

P(X = 10) = \frac{e^{-10}*(10)^{10}}{(10)!} = 0.1251

P(X \leq 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) + P(X = 10) = 0.000045 + 0.00045 + 0.0023 + 0.0076 + 0.0189 + 0.0378 + 0.0631 + 0.0901 + 0.1126 + 0.1251 + 0.1251 = 0.5831

58.31% probability that there are no more than 10 arrivals.

8 0
3 years ago
Cual es el mínimo común pultiplo de3/7,1/4,2/5,6/10,4/6
MAXImum [283]
I am not understanding what you are asking


8 0
3 years ago
A sequence is defined recursively by the formula f(n + 1) = –2f(n). The first term of the sequence is –1.5. What is the next ter
lord [1]
Hello,


f(1)=-1.5
f(2)=-2*f(1)=-2*(-1.5)=3

Answer D


3 0
3 years ago
Other questions:
  • if u have 20 square pieces of wood describe ways you could make a rectangle by placing them side by side
    9·1 answer
  • 42 = 4n -7(n-9) solve it
    13·2 answers
  • The height of this iron rod is estimated to be 100 centimeters. What is the possible error of measurement?
    5·1 answer
  • Please help with number 8!
    5·2 answers
  • Can someone help me on B and C
    13·1 answer
  • What is three fifths times 2 and five sixths
    9·1 answer
  • How many cups are in 1 quart?​
    14·1 answer
  • WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!<br> WHAT IS THE AMPLITUDE OF THIS FUNCTION
    14·1 answer
  • Identify the maximum of the graph below. Type your answer by filling in the blanks below
    15·1 answer
  • What value of c makes the equation true? <br> (PLEASE HELP, and look at the picture)
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!