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Gnom [1K]
3 years ago
14

I really don't understand number 10 please help

Mathematics
2 answers:
djyliett [7]3 years ago
8 0
Its asking what possible coordinates 
lina2011 [118]3 years ago
4 0
D. is the correct answer. 
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1. Colored copies cost 10¢ per copy and white copies
kap26 [50]

Answer:

the answer is  A

Step-by-step explanation:i just did it

your welcome

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4 years ago
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What are the solutions to the system of equations graphed below?
Morgarella [4.7K]

Answer:

looking at the straight line, it touches the axis at (-2,0) and (6,0)

Step-by-step explanation:

6 0
3 years ago
For their history project, students case to either write a report or give a presentation. Two fifth of the students wrote a repo
Gnesinka [82]

Answer: Yes. Dominic is correct

Step-by-step explanation:

We are informed that Two fifth of the students wrote a report. This also means that (2/5 × 100) = 40% = 0.4 wrote a report and 0.6 of the students gave a presentation.

From the decimals gotten, we can see that 0.6 is more than 0.4. Therefore, more students gave a presentation. This implies that Dominic is correct.

3 0
3 years ago
A metal coin has a volume of 835 mm3 and a mass of 5.67 g. What is the density of the coin?
steposvetlana [31]

Density = Mass (grams) / Volume (cubic cm)

Density = 5.67g / .835 cc

Density = 6.7904191617 g per cc

1 Cubic Centimeter = 1,000 cubic millimeters

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5 0
4 years ago
Find the solution to the differential equation dz/dt = 7te^4z that passes through the origin.
andreev551 [17]

Answer:

z=(\frac{-1}{4} )ln|1-14t^{2}|\\

Step-by-step explanation:

from the equation, \frac{dz}{dt}=7te^{4z}\\.

we can give different approach to the equation, but to make it simple and direct, let separate the equation by bringing all like terms to the same side i.e

\frac{dz}{e^{4z}}=7tdt\\e^{-4z} dz=7tdt.

if we integrate both side,

\int\limits^a_b{e^{-4z} } \,dz =\int\limits^a_b {7t} \,dt

-1/4e^{-4z} +c_{1}=7/2t^{2} +c_{2}\\-1/4e^{-4z}= 7/2t^{2} +c_{2}-c_{1}\\let c_{2}-c_{1}=c \\-1/4e^{-4z}= 7/2t^{2} +c

since the equation passes through the origin, and at the origin z=0 and t=0

we substitute this values and solve for the constant c

e^{-4*0}= 7/2*0 +c\\c=1.

If we substitute the value of c into the equation we arrive at

(-1/4)e^{-4z}= (7/2)t^{2}+1\\ e^{-4z}=1-14t^{2} \\

if we the the natural logarithm of both sides, we arrive at

-4z=ln|1-14t^{2}|\\z=(\frac{-1}{4} )ln|1-14t^{2}|\\

3 0
3 years ago
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