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rjkz [21]
3 years ago
11

HCF of (a^3+b^3 ) & (a^4+a^2b^2+b^4)?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0

Answer:

a^2-ab+b^2

Step-by-step explanation:

factorize both of them.

jenyasd209 [6]3 years ago
3 0

Answer:

Step-by-step explanation:

Remember:

a^3+b^3=(a+b)(a^2-ab+b^2)\\

a^3+b^3=(a+b)(a^2-ab+b^2)\\\\\\a^4+a^2b^2+b^4=a^4+2a^2b^2+b^4-a^2b^2\\\\=(a^2+b^2)^2-a^2b^2\\\\=(a^2+b^2-ab)(a^2+b^2+ab)\\\\HCF=a^2+b^2-ab\\

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Answer with Step-by-step explanation:

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8 0
3 years ago
I need serious answers ppl keep putting those links
ohaa [14]

Answer:

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Step-by-step explanation:

An easy way to solve this is looking at whether the line has a positive or negative slope. We read graphs from left to right so <u>if the line is increasing from left to right, it has a positive slope while a line decreasing from left to right has a negative slope</u>. Since the line shown is decreasing from left to right, it will have a negative slope and Roman is the only one out of the two that shows a negative slope. To check to see if he's correct, we can check the y-intercept. The y-intercept of the line is 8 and Roman also has 8 written in the expression. Hence, meaning Roman is correct.

Best of Luck!

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