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rjkz [21]
3 years ago
11

HCF of (a^3+b^3 ) & (a^4+a^2b^2+b^4)?

Mathematics
2 answers:
VashaNatasha [74]3 years ago
8 0

Answer:

a^2-ab+b^2

Step-by-step explanation:

factorize both of them.

jenyasd209 [6]3 years ago
3 0

Answer:

Step-by-step explanation:

Remember:

a^3+b^3=(a+b)(a^2-ab+b^2)\\

a^3+b^3=(a+b)(a^2-ab+b^2)\\\\\\a^4+a^2b^2+b^4=a^4+2a^2b^2+b^4-a^2b^2\\\\=(a^2+b^2)^2-a^2b^2\\\\=(a^2+b^2-ab)(a^2+b^2+ab)\\\\HCF=a^2+b^2-ab\\

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then divide 2070 by 150

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3 years ago
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4 years ago
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Answer:

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Step-by-step explanation:

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The corrected steps are

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