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3 years ago

What is the scale factor from the original copy?

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

Answer:

Step-by-step explanation:

Oi boa tarde tudo bem

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Whats the answer to 45=x(14-x)

ElenaW [278]

$45=x(14-x)\\ \\45=14x-x^2\\ \\x^2-14x+45=0\\ \\\Delta = b^{2}-4ac = (-14)^{2}-4*1* 45=196-180=16 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{14- \sqrt{16}}{2}=\frac{14-4}{2}= \frac{12}{2}=6\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{14+\sqrt{16}}{2}=\frac{14+4}{2}= \frac{18}{2}=9$

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3 years ago

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Abe plans to lay tiles on the areas shown. A case of tiles costs $40 and covers 15 square feet. How much does Abe need to budget

Juli2301 [7.4K]

$440

152/15 x 40 ≈ 401

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3 years ago

A pool is being drained at a rate of 120 gallons per minute.What is this rate in quarts per hour?

zysi [14]

There are 4 quarts in 1 gallon, so a rate of 120 gallons per minute converts to 4 x 120 = 480 quarts per minute. To find the per hour rate, we simply multiply our per minute rate by 60, obtaining 480 x 60 = 28800 quarts per hour.

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3 years ago

If y = 45 when x = 180, what is the y when x= 90

bearhunter [10]

Answer:

24.5

Step-by-step explanation:

Since 180 is double 90 divide 45 by 2 and you'll get 24.5

6 0

3 years ago

Which of these four sets of side lengths will form a right triangle? Set 1 4 cm, 5 cm, 6 cm Set 2 8 in., 12 in., 20 in. Set 3 10

Alenkasestr [34]

Answer: The correct option is (D) SET 4.

Step-by-step explanation: We are to select the correct set of side lengths that will form a right-angled triangle.

To form a right-angled triangle, we must have the following relation:

Perpendicular² + Base² = Hypotenuse².

Hypotenuse is the length of the largest side; perpendicular and base are the two legs of the triangle.

SET 1 : 14 cm, 5 cm, 6 cm.

We have

$5^2+6^2=25+36=61,\\\\14^2=196.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 2 : 8 in., 12 in., 20 in.

We have

$8^2+12^2=64+144=208,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 3 : 10 mm, 20 mm, 30 mm.

We have

$10^2+20^2=100+400=500,\\\\30^2=900.$

Therefore,

Perpendicular² + Base² ≠ Hypotenuse².

So, this set will not form a right-angled triangle.

SET 4 : 12 ft, 16 ft, 20 ft.

We have

$12^2+16^2=144+256=400,\\\\20^2=400.$

Therefore,

Perpendicular² + Base² = Hypotenuse².

So, this set will form a right-angled triangle.

Thus, the SET 4 will form a right-angles triangle.

Option (D) is correct.

5 0

3 years ago

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