V57 v3 is Keats becuase it’s math and not why it’s not math it’s math just holy math with gif
2y=10x-14
5x-y=7
Divide both sides by 2 in the 1st equation
y=5x-7
Now substitute is to 2nd equation
5x-5x+7=7
0=0
Therefore there is no solution or it is inconsistent
Given that a polynomial function P(x) has rational coefficients.
Two roots are already given which are i and 7+8i,
Now we have to find two additional roots of P(x)=0
Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.
conjugate of a+bi is given by a-bi
So using that logic, conjugate of i is i
also conjugate of 7+8i is 7-8i
Hence final answer for the remaining roots are (-i) and (7-8i).
So to find the mean you add up all the numbers (or the exam scores) which will get you 212 then you take the number and divide it by the total numbers in the set (how many numbers did you add up?)
212 divided by 8 is 26.5 which would be C. I hope this helps!
